120 is divisible by 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60 and 120.
No, 590 is divisible by 2, 5 and 10.
It is divisible by 2, 5 and 10 but not the rest.
Any element of the set of numbers of the form *k, where k is an integer, is evenly divisible. However, 308 is not evenly divisible by either.
no not by 10 as 216 ends in 6 not 0 same with 5 as does not end in 5 or 0 216 = 2 x 108 = 3 x 72 = 4 x 54 = 6 x 36 = 9 x 24 --------------------------------------- Last digit of 216 is even (one of {0, 2, 4, 6, 8}) so 216 is divisible by 2 6 + 1 + 2 = 9 which is divisible by 3 so 216 is divisible by 3 Last 2 digits are 16 which are divisible by 4, so 216 is divisible by 4 Last digit is not 0 nor 5, so 216 is NOT divisible by 5 216 is divisible by both 2 and 3 so 216 is divisible by 6 6 + 1 + 2 = 9, so 216 is divisible by 9 Last digit is not 0, so 216 is NOT divisible by 10 216 is divisible by 2, 3, 4, 6, 9. 216 is NOT divisible by 5 nor 10.
120 is divisible by the following numbers: 1 2 3 4 5 6 8 10 12 15 20 24 30 40 60 120.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
Since 120 ends with zero, then 120 is divisible by 5.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
because 10 is also divisible by 2 and 5.
30, 60, 90, 120, 150, 180...
Because 10 is divisible by both 2 and 5
No, 120 is not the smallest number that is divisible by 1,2,3,4,5 and 6.
10 / 2 = 5 10 / 5 = 2
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
120 is divisible by 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60 and 120.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.