Yes. Simple example:
a=(1 i)
(-i 1)
The eigenvalues of the Hermitean matrix a are 0 and 2 and the corresponding eigenvectors are (i -1) and (i 1).
A Hermitean matrix always has real eigenvalues, but it can have complex eigenvectors.
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Hermitian matrix (please note spelling): a square matrix with complex elements that is equal to its conjugate transpose.
This is the definition of eigenvectors and eigenvalues according to Wikipedia:Specifically, a non-zero column vector v is a (right) eigenvector of a matrix A if (and only if) there exists a number λ such that Av = λv. The number λ is called the eigenvalue corresponding to that vector. The set of all eigenvectors of a matrix, each paired with its corresponding eigenvalue, is called the eigensystemof that matrix
An eigenvector is a vector which, when transformed by a given matrix, is merely multiplied by a scalar constant; its direction isn't changed. An eigenvalue, in this context, is the factor by which the eigenvector is multiplied when transformed.
A complex number has an imaginary component and is of the form a + bi. (And i is the square root of -1 in this application.)A matrix is a table of numbers. For example, we might give the current (x,y,z) coordinates of a dozen asteroids using a 12 * 3 matrix.A complex matrix is a matrix of complex numbers.
It is the conjugate transpose of the matrix. Of course the conjugate parts only matters with complex entries. So here is a definition:A unitary matrix is a square matrix U whose entries are complex numbers and whose inverse is equal to its conjugate transpose U*. This means thatU*U = UU* = I. Where I is the identity matrix.