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A diagonal is a line between two vertices that is not an edge. As two vertices are connected by an edge, the number of diagonals from a vertex is the number of vertices (or sides or angles) less 3; as each diagonal is counted twice, once for the vertex at each end of it: number_of_diagonals = ½ × number_of_vertices × (number_of_vertices - 3) For a nonagon, it has 9 vertices → number_of_diagonals = ½ × 9 × (9 -3) = ½ × 9 × 6 = 27.
Given: The area of the rhombus is 120 square feet The diagonal of the rhombus is 16 feet think of the rhombus being two identical triangles, connected at their base which is 16 feet long. Each of them would then have an area of 60 feet. Now, in a triangle, area = (base * height) / 2 the area is already given as 60, and the base as 16 we can say then: 60 = (16 * h) / 2 ∴60 = 8h ∴h = 7.5 Now, that 7.5 is half the length of the rhombus (as it's the height of one of our triangles, which each are half our rhombus). So we know that that the other diagonal on the rhombus is twice that. In other words, the answer is 15.
The only pyramid with a square base that has equilateral faces, is one where the diagonal of the base is exactly twice as long as the pyramid is high.
thats a bit of a mouthful...