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The shortest path between two points is a straight line. This is a mathematical fact, which can be proven in another question.

The diagonal of a quadrilateral is a straight line between two opposing (non-adjacent) vertices. The perimeter of a quadrilateral will include two separate paths between the same vertices. The difference is that these two paths are each composed of two linked line segments, so each of these paths will be longer than the diagonal.

Therefore, the length of the perimeter of a quadrilateral will be greater than twice the length of either diagonal.

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Q: Prove that the perimeter of a quadrilateral is greater than the sum of the length of its diagonal?

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The length of the other diagonal works out as 12cm

The perimeter of this square is 56.569 meters.

The perimeter of a quadrilateral is always equal to the sum the lengths of its four sides. So perimeter = Side1 +Side2 + Side3 +Side4. If the quadrilateral happens to be a parallelogram, a quick way to calculate the perimeter is 2 x length of base + 2 x length of height.

The side lengths are 12 m and the diagonal is 16.97 m

12.73 feet

Related questions

it is impossible for a diagonal of a rhombus to be the same length as its perimeter

A "regular quadrilateral" is a square. The word "radius" isn't used for squares (or polygons in general). To get the length of a side, divide the perimeter by 4. To get the diagonal of a square, multiply the length of a side by the square root of 2.

The length of the other diagonal works out as 12cm

The length of one diagonal is not sufficient to determine its sides and so its perimeter.

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

The perimeter of this square is 56.569 meters.

The perimeter of a quadrilateral is always equal to the sum the lengths of its four sides. So perimeter = Side1 +Side2 + Side3 +Side4. If the quadrilateral happens to be a parallelogram, a quick way to calculate the perimeter is 2 x length of base + 2 x length of height.

~26.16 units.

The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm

The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.

It depends on 2.35m what: length of sides, diagonal, perimeter.

The perimeter is 18 feet.

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