3
5x2 + 3x + 8x2 = 13x2 + 3x = x(13x + 3)
5x2 + 3x - 2 is a polynomial so, we can say: p(x) = 5x2 + 3x - 2which is of the form of ax2 + bx + cFirst of all multiply the coefficient of x2 with cHere a = 5 and c = -2ac = 5(-2) = -10Break the coefficient of x i.e. b into two numbers such that the product of the numbers is equal to ac.We can't break 3 into two numbers so that their product is -10.So, it is not possible to factor p(x).
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
(x + 3)(3x^2 - 4x + 6)
5x2 + 3x - 1 does not have rational factors.
3
5x2 + 3x + 8x2 = 13x2 + 3x = x(13x + 3)
5x2 + 3x - 2 is a polynomial so, we can say: p(x) = 5x2 + 3x - 2which is of the form of ax2 + bx + cFirst of all multiply the coefficient of x2 with cHere a = 5 and c = -2ac = 5(-2) = -10Break the coefficient of x i.e. b into two numbers such that the product of the numbers is equal to ac.We can't break 3 into two numbers so that their product is -10.So, it is not possible to factor p(x).
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
5x2y = 3x - 6y 5x2y + 6y = 3x y(5x2 + 6) = 3x y = (3x)/(5x2 + 6) This is a rational function.
(x + 3)(3x^2 - 4x + 6)
x^2 + 3x - 2; -x^2 - 3x + 2andx - 1; 1 - x
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
Distance travelled = 5x3 - 6x2 + 3x + 14 = 5x3 + 5x2 - 11x2 - 11x + 14x + 14 = 5x2(x + 1) - 11x(x + 1) + 14(x + 1) = (x + 1)(5x2 - 11x + 14) Then time = distance/rate = (x + 1)(5x2 - 11x + 14) / (x+1) = 5x2 - 11x + 14
If that's 9a2, the answer is a(a2 - 9a + 3) x(5x2 + 3x - 1) -8d(d2 + 3d + 1)