The area of a rhombus is calculated by multiplying the base x the vertical height.
Base = Area/Height = 7886.2/95.7 = 82.405 cm (to 3 dp)
Base multiplied by its perpendicular height and measured in square units.
Given: The area of the rhombus is 120 square feet The diagonal of the rhombus is 16 feet think of the rhombus being two identical triangles, connected at their base which is 16 feet long. Each of them would then have an area of 60 feet. Now, in a triangle, area = (base * height) / 2 the area is already given as 60, and the base as 16 we can say then: 60 = (16 * h) / 2 ∴60 = 8h ∴h = 7.5 Now, that 7.5 is half the length of the rhombus (as it's the height of one of our triangles, which each are half our rhombus). So we know that that the other diagonal on the rhombus is twice that. In other words, the answer is 15.
Area = Base * Height so Base = Area/Height
The area of a rhombus is calculated by multiplying the base x the vertical height.
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm? . Area = base * height Altitude = height. Altitude = 4 cm . A rhombus has all 4 sides equal, so the base = 6 cm . Area = base * height . Area = ____sq. cm.
Area of a rhombus: base times perpendicular height Or area of a rhombus: 0.5 times product of its diagonals
Base = Area/Height = 7886.2/95.7 = 82.405 cm (to 3 dp)
Base multiplied by its perpendicular height and measured in square units.
Area equals base times height. The perimeter is 4 times the length of one side.
A=BxH =7x3 =21ft squared
Given: The area of the rhombus is 120 square feet The diagonal of the rhombus is 16 feet think of the rhombus being two identical triangles, connected at their base which is 16 feet long. Each of them would then have an area of 60 feet. Now, in a triangle, area = (base * height) / 2 the area is already given as 60, and the base as 16 we can say then: 60 = (16 * h) / 2 ∴60 = 8h ∴h = 7.5 Now, that 7.5 is half the length of the rhombus (as it's the height of one of our triangles, which each are half our rhombus). So we know that that the other diagonal on the rhombus is twice that. In other words, the answer is 15.
Its area is base times perpendicular height or 0.5 times the product of its diagonals
Area = Base * Height so Base = Area/Height
A rhombus is a quadrilateral where all sides have the same length. Rhombuses have some special properties that help you determine their measurements. Sides: if you know the length of one side, you know the length of the rest of the sides. Angles: the angles which are adjacent to each other in a rhombus are supplements to each other. So if you have a rhombus with angles A, B, C and D, then A + B = 180 degrees, and A + D = 180 degrees. This also means that B = D. And because the sum of the angles of any quadilateral is 360 degrees, A = C. Area: The area of a rhombus is the base * height, where the base is an arbitrary side of the rhombus and the height is the distance between the base and the opposite side of the rhombus. If you draw a perpendicular line between the base and the opposite side, the length of that line will be the height.
If you multiply the lengths of the two diagonals, and divide by 2, you get the area of a rhombus. How does this work: Call the diagonals A & B for clarity. Diagonal A will split the rhombus into 2 congruent triangles. Looking at one of these triangles, its base is the diagonal A, and its height is 1/2 of diagonal B. So the area of one of the triangles is (1/2)*base*height = (1/2)*A*(B/2) = A*B/4. The other triangle has the same area, so the two areas together make up the whole rhombus = 2*(A*B/4) = A*B/2.