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2NH4NO3->2N2+O2+4H2O
2NaH2 + O2 yields 2Na + 2H2O
Copper metal can be prepared by roasting copper ore, which can contain cuprite (Cu2S) and Copper (II) sulfide. Cu2S + O2 -> 2Cu + So2 CuS + O2 -> Cu + SO2 Suppose an ore sample contains 11.0% impurity in addition to a mixture of CuS and Cu2S. Heating 100.0 g of the mixture produces 75.4 g of copper metal with a purity of 89.5%. What is the weight percent of CuS in the ore? The weight percent of Cu2S? Clicked enter too fast, sorry.
Simple application of Pythagoras Congruent side becomes the hypotenuse of a right-angled triangle with a known side of 5 (half the base). Doing the math we get the following: H2 = O2 + A2 92 = O2 + 52 rearranging we get O2 = 92 - 52 O2 = 81 - 25 O2 = 56 therefore O = √56 which is approximately 7.48 to decimal places
A molecule of two atoms is always linear.