The lower bound of 3.0 is 3.0
If I understand your question correctly, such a sequence is an = x cos(πx). It has neither an upper nor lower bound. It's divergent, but its limit is neither infinity nor negative infinity.
The upper bound of a number is the smallest whole number that is greater than or equal to the given number. In this case, the upper bound of 6800 is 6800 itself. The lower bound of a number is the largest whole number that is less than or equal to the given number. Therefore, the lower bound of 6800 is also 6800.
If the range is the real numbers, it has a lower bound (zero) but no upper bound.
The answer depends on the level of accuracy of the value 0.
Option Explicit makes the declaration of Variables Mandatory while Option Base used at module level to declare the default lower bound for array subscripts. For eg. Option Base 1 will make the array lower bound as 1 instead of 0. by Munendra
Lower bound is 17.6 and upper bound is 17.8
The lower bound of 3.0 is 3.0
The answer is B.
If I understand your question correctly, such a sequence is an = x cos(πx). It has neither an upper nor lower bound. It's divergent, but its limit is neither infinity nor negative infinity.
You cannot list them: unless the inequality is trivial, since there are infinitely many real numbers in any range. You need toidentify the lower bound;determine whether or not the lower bound is included (
The lower bound is 16.35
The upper bound of a number is the smallest whole number that is greater than or equal to the given number. In this case, the upper bound of 6800 is 6800 itself. The lower bound of a number is the largest whole number that is less than or equal to the given number. Therefore, the lower bound of 6800 is also 6800.
-5 is lower
j
bcoz the energy of bound system is always negative
The lower bound is 0.5 less and the upper bound is 0.5 more.