The upper bound of a number is the smallest whole number that is greater than or equal to the given number. In this case, the upper bound of 6800 is 6800 itself. The lower bound of a number is the largest whole number that is less than or equal to the given number. Therefore, the lower bound of 6800 is also 6800.
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If the range is the real numbers, it has a lower bound (zero) but no upper bound.
no won noes * * * * * It means that there is an upper and lower bound or limit. There is the lower bound such that you exclude any smaller numbers, and an upper bound such that you exclude bigger numbers. What you do wit hnumbers that are equal to the bounds depends on the nature of the bounds.
The answer depends on the level of accuracy of the value 0.
They’re the ‘real value’ of a rounded number. Upper and Lower Bounds are concerned with accuracy. Any measurement must be given to a degree of accuracy, e.g. 'to 1 d.p.', or ' 2 s.f.', etc. Once you know the degree to which a measurement has been rounded, you can then find the Upper and Lower Bounds of that measurement. Phrases such as the 'least Upper Bound' and the 'greatest Lower Bound' can be a bit confusing, so remember them like this: the Upper Bound is the biggest possible value the measurement could have been before it was rounded down; while the Lower Bound is the smallest possible value the measurement could have been before it was rounded up.
If I understand your question correctly, such a sequence is an = x cos(πx). It has neither an upper nor lower bound. It's divergent, but its limit is neither infinity nor negative infinity.