Well you see black people are useless. Whoever made the black child is obviously an ape of some sort.
The noun coat is a count noun: one coat, two coats.
Coat is a count noun: one coat, two coats, three coats.
The word coat has one syllable.
Without a coat the coat keeps the cold air in, like a thermos flask we learnt this in year 3....
No, two smooth coat guinea pigs will not produce a rough coat guinea pig. Coat type in guinea pigs is determined by genetics, so if the parents both have smooth coats, their offspring will also have smooth coats.
A breeder could determine if a rough-coated guinea pig is homozygous or heterozygous by conducting a test mating. Breeding the rough-coated guinea pig with a smooth-coated guinea pig would show if the rough coat is dominant or recessive. If all the offspring have rough coats, it indicates the rough-coated guinea pig is homozygous for the trait. If both rough and smooth-coated offspring are produced, then the rough-coated guinea pig is heterozygous.
The black guinea pig is likely heterozygous (Bb) for coat color, while the white guinea pig is homozygous recessive (bb). The black guinea pig passes on a black allele to all offspring, resulting in 4 black (Bb) and 2 white (bb) offspring.
A black guinea pig would have a black coat color, while a white guinea pig would have a white coat color. Color variation in guinea pigs is due to different alleles of the gene controlling coat color, resulting in different phenotypes.
The black guinea pig is homozygous for the black coat color gene, while the albino guinea pig is homozygous for the albino gene. When the albino is crossed with a black guinea pig, all the offspring inherit the black coat color gene but show the dominant black phenotype. When the albino is crossed with a second black guinea pig that is heterozygous for the gene, it leads to a 3:1 ratio of black to albino offspring due to the inheritance of the albino gene.
If you look up genetics in BrainPop, it will show you. The guinea pig must have an ancestor that had rough skin.
The black-coated animal from the initial cross must have been heterozygous (Bb), as it passed on a black allele to all offspring. The white-coated animal from the cross was homozygous recessive (bb). The offspring all inherited one black allele from the black-coated parent and one white allele from the white-coated parent, resulting in a genotype of Bb for all offspring and a black coat color.
The Bird of Paradise is the most famous bird from New Guinea. It is PNG's coat of arms.
The adult size of a rex guinea pigs vaires but they are very cleen and have a wire coat.
The "B" allele codes for a black coat color, so offspring with a BB or Bb genotype will both have a black coat due to the dominant nature of the "B" allele. The presence of at least one "B" allele ensures that the offspring will express the black coat color phenotype.
If by "English Smooth Coat" , you mean sheltie, then you can end up with a couple of both in the litter. Then a again, you could end up with a mix.
Chances are, white. Colour is usually inherited from the mother of the two parents, however there are exceptions.