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Yes, but you cannot combine them.

Thus, 2x2 and 1/x can be added to give 2x2 + 1/x

but they cannot be combined into a single term.

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Q: Can we add dissimilar term
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Related questions

What is the definition of dissimilar term in algebra?

dissimilar terms are terms that do not have the same variable or the variable do not contain the same number of exponents


Adding dissimilar fractions and whole numbers?

1. change the dissimilar fractions to similar fractions by getting the L.C.D or the least common denominator. 2. add the whole numbers and write down the given denominator. 3. reduce the answer to lowest term if possible.


How do you add a dissimilar fraction?

By finding their lowest common denominator


Meaning of adding of dissimilar fractions?

Adding dissimilar fractions involves finding a common denominator for the fractions before adding them together. This common denominator is the least common multiple of the denominators of the fractions being added. Once the fractions have the same denominator, you can add the numerators together while keeping the denominator the same. Finally, simplify the resulting fraction if possible by reducing it to its simplest form.


What does the math term dissimilar mean?

Not similar, i.e., different.


How do you add and subtract dissimilar fractions?

Make the fractions equivalent then subtract


Why can't you add dissimilar terms?

because the operation "add" is only defined for members of the same set


How do you add and subtract dissimilar fractiono?

By finding the lowest common multiple of the denominators.


How do you add or subtract radicals with similar and dissimilar radicands?

See related link.


How do you add the dissimilar fraction?

You have to convert them to equivalent similar fractions (fractions with the same denominator) first.


How do you add or subtract dissimilar fractions with or without regrouping?

What is the answer for 8 1/3 - 5 2/6


How do you add and subtract integers with similar sides and dissimilar sides?

Integers do not have sides so the question does not make sense.