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Three times the first of three consecutive odd integers is three more than the twice and the third What is the average of the three integers?
Let the first of the three odd consecutive integers be x, so that the second of these integers would be x + 2, and the third one would be x + 4. We have: 3x = 2[(x + 2)+ (x + 4)] + 3 3x = 2(2x + 6) +3 3x = 4x + 12 + 3 (subtract 4x to both sides) -x = 15 (multiply by -1 to both sides) x = -15 (the first one) So the integers are -15, -13, and -11. The average of those integers is (-15 + -13 + -11)/2 = -39/2 = -19.5.
What is 2x plus 22 equals x?
2x + 22 = x Subtract x from both sides: x + 22 = 0 Subtract 22 from both sides: x = -22
How many right-angled triangles are there with sides that are all integers less than 50 units?
There are 18, but only 7 primitive ones. The rest are similar to the primitive triangles : for example (15, 50, 25) is similar to (3, 4, 5).
How do you solve 3x-7 equals 5x plus 3?
First you subtract 3x from both sides and get -7=2x+3. Then subtract 3 from both sides and get -10=2x. Then divide both sides by 2 and x=-5.
How would you solve 70 equals 81 - n?
70 = 81-n subtract 70 from both sides 0 = 11 - n subtract 11 from both sides -11 = -n divide both sides by -1 11 = n
What Four consecutive odd integers whose sum is -220?
Let x be the smallest of the consecutive odd integers. Since consecutive odd integers differ by 2, we havex + (x + 2) + (x + 4) + (x + 6) = -2204x + 12 = -220 (subtract 12 to both sides)4x = -232 (divide by 4 to both sides)x = -58Thus, the four consecutive odd integers whose sum is -220 are -58, -56, -54, and -52.
What is the sum of two consecutive integers is 237?
Algebraically, X = integers. X + (X + 1) = 237 gather all terms on the left 2X + 1 = 237 subtract 1 from each side 2X = 236 divide both sides integers by 2 X = 118 --------------so, X + 1 = 119 ----------------so, The two consecutive integers that = 237 are 118 and 119 -------------------
How do you spell scalene?
That is the correct spelling of "scalene" (in one sense a triangle with three dissimilar sides).
Is Has two congruent sides?
Yes. When you subtract two, you get two congruent sides.
find three consecutive odd integers whose sum is 471?
Let the odd integers be , n, n+2 & n+4 Hence n + (n+2) + (n +4) = 471 Add LHS 3n + 6 = 471 Subtract '6' from both sides 3n = 465 Divide both sides by '3' n = 155 n + 2 = 157 n + 4 = 159 Hence the integers are 155,157 & 159.
What is 9y plus 4 equals 2y plus 25?
9Y + 4 = 2Y + 25 subtract 2Y from both sides 7Y + 4 = 25 subtract 4 from both sides 7Y = 21 divide both sides integers by 7 (7/7)Y = 21/7 Y = 3 -----------------check in original equation 9(3) + 4 = 2(3) + 25 27 + 4 = 6 + 25 31 = 31 ---------------checks
Three times the first of three consecutive odd integers is three more than the twice and the third What is the average of the three integers?
Let the first of the three odd consecutive integers be x, so that the second of these integers would be x + 2, and the third one would be x + 4. We have: 3x = 2[(x + 2)+ (x + 4)] + 3 3x = 2(2x + 6) +3 3x = 4x + 12 + 3 (subtract 4x to both sides) -x = 15 (multiply by -1 to both sides) x = -15 (the first one) So the integers are -15, -13, and -11. The average of those integers is (-15 + -13 + -11)/2 = -39/2 = -19.5.
What is 2x plus 22 equals x?
2x + 22 = x Subtract x from both sides: x + 22 = 0 Subtract 22 from both sides: x = -22
How many right-angled triangles are there with sides that are all integers less than 50 units?
There are 18, but only 7 primitive ones. The rest are similar to the primitive triangles : for example (15, 50, 25) is similar to (3, 4, 5).
How do you solve 3x-7 equals 5x plus 3?
First you subtract 3x from both sides and get -7=2x+3. Then subtract 3 from both sides and get -10=2x. Then divide both sides by 2 and x=-5.
If the sum of the first two of the five consecutive odd integers is 52what is the sum of the last two integers?
Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).
Find two consecutive even integers such that the smaller added to two times the larger gives a sum of 16?
4+(6+6) All these words in mathematics are represented by an equation. Write and solve it to find those integers. If the first integer is x, the second one will be x + 2 (since consecutive even integers differ by 2). So we have: x + 2(x +2) = 16 x + 2x + 4 = 16 3x + 4 = 16 subtract 4 from both sides 3x = 12 divide by 3 both sides x = 4 Thus the integers are 4 and 6.
