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Three times the first of three consecutive odd integers is three more than the twice and the third What is the average of the three integers?
Let the first of the three odd consecutive integers be x, so that the second of these integers would be x + 2, and the third one would be x + 4. We have: 3x = 2[(x + 2)+ (x + 4)] + 3 3x = 2(2x + 6) +3 3x = 4x + 12 + 3 (subtract 4x to both sides) -x = 15 (multiply by -1 to both sides) x = -15 (the first one) So the integers are -15, -13, and -11. The average of those integers is (-15 + -13 + -11)/2 = -39/2 = -19.5.
What is 2x plus 22 equals x?
2x + 22 = x Subtract x from both sides: x + 22 = 0 Subtract 22 from both sides: x = -22
How many right-angled triangles are there with sides that are all integers less than 50 units?
There are 18, but only 7 primitive ones. The rest are similar to the primitive triangles : for example (15, 50, 25) is similar to (3, 4, 5).
How do you solve 3x-7 equals 5x plus 3?
First you subtract 3x from both sides and get -7=2x+3. Then subtract 3 from both sides and get -10=2x. Then divide both sides by 2 and x=-5.
How would you solve 70 equals 81 - n?
70 = 81-n subtract 70 from both sides 0 = 11 - n subtract 11 from both sides -11 = -n divide both sides by -1 11 = n
