There is not such set of integers.
The greatest integer is 24.
There are none. The only four consecutive integers totaling 90 are 21, 22, 23 and 24.
There is no set of six consecutive integers for -4.
Let the two consecutive integers be ( x ) and ( x + 1 ). According to the problem, we have the equation ( 4(x + 1) = 3x + 28 ). Simplifying this gives ( 4x + 4 = 3x + 28 ), which leads to ( x = 24 ). Thus, the two consecutive integers are 24 and 25.
24 + 26 + 28 + 30 = 108
The greatest integer is 24.
There are none. The only four consecutive integers totaling 90 are 21, 22, 23 and 24.
There is no set of six consecutive integers for -4.
Let the two consecutive integers be ( x ) and ( x + 1 ). According to the problem, we have the equation ( 4(x + 1) = 3x + 28 ). Simplifying this gives ( 4x + 4 = 3x + 28 ), which leads to ( x = 24 ). Thus, the two consecutive integers are 24 and 25.
24 + 26 + 28 + 30 = 108
22 + 23 + 24 + 25 = 94
n(n+2)(n+4) = 24
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
22+23+24+25 = 94
4 + 6 + 8 = 18, 6 + 8 + 10 = 24. There is no answer to your question.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
-4 and -5