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A square and a triangle have equal areas and a side of the square is 10 inches and the base of the triangle is 10 inches then what is the height of the triangle?
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
The base of a triangle is equal to 4 what is the height of the triangle if the area is 28?
If the base of a triangle is b and the height of the triangle is h, the area of the triangle is given by the formula: area = 0.5 x b x h.As such, in your case we have 28 = 0.5 x 4 x h, which means that h = 14.
Find the surface area of a triangular prism with height 30 in and a right triangle base with side lengths 15 in and 20 in and hypotenuse length 25 in?
Surface area = 2 x area_triangular_ends + areas_of_3_rectangular_faces Surface area = 2 x (15 x 20)/2 + 30 x 15 + 30 x 20 + 30 x 25 = 15 x 20 + 30 x (15 + 20 + 25) = 300 + 30 x 60 = 2100 in2
What is the area of an equilateral triangle of side 2a?
The height of an equilateral triangle is √3/2 x side_length. So for an equilateral triangle of side length 2a, the area is: area = 1/2 x base x height 1/2 x (2a) x (√3/2 x 2a) = √3 a2
How do you find the area of an acute triangle?
The area of any triangle is (1/2 the length of its base) x (its height).
