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A square and a triangle have equal areas and a side of the square is 10 inches and the base of the triangle is 10 inches then what is the height of the triangle?
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
The base of a triangle is equal to 4 what is the height of the triangle if the area is 28?
If the base of a triangle is b and the height of the triangle is h, the area of the triangle is given by the formula: area = 0.5 x b x h.As such, in your case we have 28 = 0.5 x 4 x h, which means that h = 14.
Find the surface area of a triangular prism with height 30 in and a right triangle base with side lengths 15 in and 20 in and hypotenuse length 25 in?
Surface area = 2 x area_triangular_ends + areas_of_3_rectangular_faces Surface area = 2 x (15 x 20)/2 + 30 x 15 + 30 x 20 + 30 x 25 = 15 x 20 + 30 x (15 + 20 + 25) = 300 + 30 x 60 = 2100 in2
What is the area of an equilateral triangle of side 2a?
The height of an equilateral triangle is √3/2 x side_length. So for an equilateral triangle of side length 2a, the area is: area = 1/2 x base x height 1/2 x (2a) x (√3/2 x 2a) = √3 a2
How do you find the area of an acute triangle?
The area of any triangle is (1/2 the length of its base) x (its height).
What is the area of triangle with a base 20 feet long and a height of 40 feet?
area of triangle = 0.5 x base x height area = 0.5 x 20 x 40 area = 400 ft2
What is the area of a triangle with base 6 height 4?
The formula for area of a triangle is: Base X Height divided by 2 So a base of 6 and a height of 4 6 X 4=24 24/2=12 The area of your triangle is 12 units squared.
What is the area of a right triangle with sides of 7 24 and 25?
First make sure that this is a valid right triangle Since 25 x 25 = (24 x 24) + (7 x 7) we are assured that it is truly a right triangle with 25 as the hypotenuse and the other two sides being 7 and 24 linear units. Then we can use the formula for area of triangle as (1/2) x base x height which in our case would be (1/2) x 7 x 24 = 7 x 12 = 84 square units
Triangle has a base of 6m and height of 8m what is the area of the triangle?
(6 x 8) / 2 ie 24 sqm
A square and a triangle have equal areas and a side of the square is 10 inches and the base of the triangle is 10 inches then what is the height of the triangle?
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
What is the area of a triangle 6m length 8m width?
Assuming that the width of the triangle is the base of the triangle and the the length is height we can calculate area as followed: 1/2 Base x Height = Area of a Triangle (8 meters ÷ 2) x 6 meters = 4 meters x 6 meters = 24 meters².
What is the height of a triangle with an area of 24 square centimeters and a base of 6 centimeters?
8 centimeters The formula for the area of a triangle is: A = 1/2 x b x h area equals one half times the base times the height. 24 = 1/2 x 6 x h h = 8cm
What is the area of a triangle if the length is ten and the height is twenty?
If the given length is the measure length of the base of the triangle, then the area of the triangle is: A = (bh)/2 = (10 x 20)/2 = 100.
Triangle's area is 12 of base what?
Area of triangle is 1/2 base x height. So 12=1/2 bh b=24/h
A right triangle has legs 6cm and 8cm How far from the vertex must this triangle be cut by a line parallel to the longer leg so that the area of the smaller right triangle is equal to the area of the?
it is 24in The area of the first triangle is 24 [(6*8)/2]. The area of the smaller triangle is 12 [24/2]. The two legs will have a relationship of [4/3x to x], the same as any right triangle.
What is the area of a triangle with a base and height of 7 inches 24 inches?
Formula for area of a triangle= base x height÷ 2 so...area=7x24÷2area=168÷2area=84
ABCD is a gm and X is the mid-pint of AB. If Ar.(AXCD)24cm2 find Ar. of ABCD?
To find the area of quadrilateral ABCD, we can use the property of midpoints in geometry. Since X is the midpoint of AB, the area of triangle AXC is half of the area of triangle ABC. Therefore, if the area of AXCD is 24 cm², then the area of triangle ABC is also 24 cm². Thus, the total area of quadrilateral ABCD, which consists of triangles AXC and BXC, is 48 cm² (24 cm² + 24 cm²).
