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no physically you cannot because before an odd number is a even number.

Q: Can you get a odd number and subtraction 1 and get a odd number?

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The number 1 is an odd number.

An odd number multiplied by another odd number will always equal an odd number. Therefore odd2 = odd x odd = odd number. eg 32 = 3 x 3 = 9. Take away 1 and you will have on even number.

odd

Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.

*1 is an odd number * 0 is an even number

Related questions

Alternate addition and subtraction of consecutive odd numbers. +3, -5, + 7, -9 The next number is 8.

Every odd number leaves a remainder of 1 when divided by 2. Therefore, every odd number is of the form 2k +1 where k is some integer.Suppose 2m + 1 and 2n + 1 are two odd numbers.Then (2m + 1) - (2n + 1) = 2m + 1 - 2n - 1 = 2m - 2n = 2*(m - n)By the closure property of integers under addition (and subtraction), m and n being integers implies than (m - n) is an integer. Therefore 2*(m - n) is an even integer.

The number 1 is an odd number.

Answer:1 is an odd number If you need to learn math go to the web site in the link below

No. The sum of 1 odd number and 1 even number must always be odd.

odd

199 The first odd number is 1 The second odd number is 3 The rth odd number is thus 2r - 1 Thus the 100th odd number is 2 x 100 - 1 = 199.

1 is the 1st odd number 3 is the 2nd odd number 5 is the 3rd odd number and so on 7 is the 4th odd number and so on if x is the 1000th odd number then x=2*1000-1=1999

The smallest odd number is 1.

The nth odd number is 2n - 1 So 102nd odd number is 2*102 - 1 = 204 - 1 = 203

799 would be the 400th odd number even if '1' were not the first one.

yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.