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Well, the question is why. The first number is "even" + 1. Multiply both of these by

your odd number. Now the "even" times "odd" is even, because every "1" in the odd

number becomes a "2". And then the remaining 1 times "odd" must be odd, which is

an even +1. Add it all up and you get evens everywhere except that final "1". So the

result is even + 1 which is odd.

There is a quicker way if you know how to multiply bracketed terms:

odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.

==========================

You've just read a truly impressive answer to a question slightly different from the

one that was asked.

The part of the question that comes after "Why if ..." is a false statement.

If you multiply odd number with another number, the result is odd number ONLY

if the nother number is also odd number.

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Q: Why if you multiply odd number with another number the result is always odd number?
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