If you are thinking of a mgic square, the answer is NO. The nine numbers sum to 45 so if you have three rows with equal sums, that sum can only be 45/3 = 15. You can have two rows, each adding to 17, and using the digits only once, but you will not use all digits.
No because you can't put into even rows
Draw either 3 rows of 5 columns or 5 rows of 3 columns.
26 shells, 3 rows -> 5 per row with 1 remaining 19 pennies, 5 rows -> 3 per row with 4 remaining 17 balloons, 7 rows -> 2 per row with 3 remaining
1 row of 180 - 2 rows of 90 - 3 rows of 60 - 4 rows of 45 - 5 rows of 36 - 6 rows of 30 - 9 rows of 20 - 10 rows of 18 - 12 rows of 15 - 15 rows of 12 - 18 rows of 10 - 20 rows of 9 - 30 rows of 6 - 36 rows of 5 - 45 rows of 4 - 60 rows of 3 - 90 rows of 2 - 180 rows of 1 - total of 18 ways within the limits of the question
Of course. You have a choice of several different lovely arrangements:18 rows with 1 in each row9 rows with 2 in each row6 rows with 3 in each row
If you are thinking of a mgic square, the answer is NO. The nine numbers sum to 45 so if you have three rows with equal sums, that sum can only be 45/3 = 15. You can have two rows, each adding to 17, and using the digits only once, but you will not use all digits.
Idk but i think you put them in 5 rows of 6 cause 6 times 5 = 30
No because you can't put into even rows
18
This is a square matrix where the number of rows and the number of columns are equal.
Draw either 3 rows of 5 columns or 5 rows of 3 columns.
63
26 shells, 3 rows -> 5 per row with 1 remaining 19 pennies, 5 rows -> 3 per row with 4 remaining 17 balloons, 7 rows -> 2 per row with 3 remaining
18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1
37
because that will equal 22 nice even rows of 6 students