2 7 6 9 5 1 4 3 8
18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1
The number of rows and the number of chars in that row give you the factor pairs of 18. If you list the number of rows when the 18 chairs can be arranged in rows with an equal number in each row, then this list is the factors of 18. 18 chairs can only be arranged in: 1 row of 18 chairs (1 × 18 = 18) 2 rows of 9 chairs (2 × 9 = 18) 3 rows of 6 chairs (3 × 6 = 18) 6 rows of 3 chairs (6 × 3 = 18) 9 rows of 2 chairs (9 × 2 = 18) 18 rows of 1 chair (18 × 1 = 18) The factors of 18 are thus: 1, 2, 3, 6, 9, 18.
63 / 7 = 9. Therefore b = 9
nothing can divide 7. 9 and 3 equally!
If I am getting what you are saying, then no. 3 rows of 9 and 2 rows equals 5 rows. 5*9=45 and 7*9=63
2 7 6 9 5 1 4 3 8
18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1
no
No.
No.
It is 7 lots of 9 = 7*9 = 63.
16
1 row of 180 - 2 rows of 90 - 3 rows of 60 - 4 rows of 45 - 5 rows of 36 - 6 rows of 30 - 9 rows of 20 - 10 rows of 18 - 12 rows of 15 - 15 rows of 12 - 18 rows of 10 - 20 rows of 9 - 30 rows of 6 - 36 rows of 5 - 45 rows of 4 - 60 rows of 3 - 90 rows of 2 - 180 rows of 1 - total of 18 ways within the limits of the question
4/7 = 0.57145/9 = 0.5555so 4/7 is not equal to 5/9
The number of rows and the number of chars in that row give you the factor pairs of 18. If you list the number of rows when the 18 chairs can be arranged in rows with an equal number in each row, then this list is the factors of 18. 18 chairs can only be arranged in: 1 row of 18 chairs (1 × 18 = 18) 2 rows of 9 chairs (2 × 9 = 18) 3 rows of 6 chairs (3 × 6 = 18) 6 rows of 3 chairs (6 × 3 = 18) 9 rows of 2 chairs (9 × 2 = 18) 18 rows of 1 chair (18 × 1 = 18) The factors of 18 are thus: 1, 2, 3, 6, 9, 18.
Either 5 rows of 7 students - or - 7 rows of 5 students. --------------------------------------------------------- or 1 row of 35 students or 35 rows of 1 student (like in an exam hall)