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Consider the word Mississippi find the total number of distinct permutations of its letters?
There are 11 letters in all, so there are a total of 11! = 39,916,800 permutations. The letter 'i' appears 4 times, so every distinct permutation will be duplicated 4! = 24 times, so we divide the total by 24. Similarly, the letter 's' appears 4 times so we divide again by 24. Finally, we divide by two because half the remaining permutations have transposed the letter p. Thus we get 11! / (4! * 4! * 2!) = 34,650 distinct permutations.
What else can I help you with?
How many permutations of the letters a through J are there?
The letters from a to J consist of 10 distinct letters. The number of permutations of these letters is calculated using the factorial of the number of letters, which is 10!. Therefore, the total number of permutations is 10! = 3,628,800.
How many permutations of the letters in the word noon are there?
The word "noon" consists of 4 letters, where 'n' appears twice and 'o' appears twice. To find the number of distinct permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \cdot n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of permutations is ( \frac{4!}{2! \cdot 2!} = \frac{24}{4} = 6 ). Therefore, there are 6 distinct permutations of the letters in the word "noon."
How many permutation are possible of the letters in the word numbers?
The word "numbers" consists of 7 distinct letters. The number of permutations of these letters is calculated using the factorial of the number of letters, which is 7!. Therefore, the total number of permutations is 7! = 5,040.
What are the distinct letters from MISSISSIPI?
The distinct letters in the word "MISSISSIPPI" are M, I, S, and P. There are four unique letters in total.
How many permutations are in the word freezer?
The word "freezer" has 7 letters, with the letter "e" appearing twice and the letter "r" appearing twice. The number of distinct permutations can be calculated using the formula for permutations of a multiset: ( \frac{n!}{n_1! , n_2! , \ldots , n_k!} ), where ( n ) is the total number of letters and ( n_i ) are the frequencies of the repeated letters. Thus, the number of permutations is ( \frac{7!}{2! \times 2!} = \frac{5040}{4} = 1260 ). Therefore, there are 1,260 distinct permutations of the word "freezer."
How many permutations of the letters a through J are there?
The letters from a to J consist of 10 distinct letters. The number of permutations of these letters is calculated using the factorial of the number of letters, which is 10!. Therefore, the total number of permutations is 10! = 3,628,800.
How many permutations of letters in word swimming?
The number of permutations of the letters SWIMMING is 8 factorial or 40,320. The number of distinct permutations, however, due to the duplication of the letters I and M is a factor of 4 less than that, or 10,080.
How many permutations of the letters in the word Louisiana are there?
The number of permutations of the letters in the word LOUISIANA is 9 factorial or 362,880. However, since the letters I and A are each repeated once, you need to divide that by 4 to determine the number of distinct permutations, giving you 90,720.
How many distinguishable permutations are there of the letters in the word effective?
The number of permutations of the letters EFFECTIVE is 9 factorial or 362,880. To determine the distinct permutations, you have to compensate for the three E's (divide by 4) and the two F's (divide by 2), giving you 45,360.
How many arrangements of the letters in the word SCHOOLS are there?
The number of permutations of the letters in the word SCHOOLS is the number of permutations of 7 things taken 7 at a time, which is 5040. However, since two of the letters, S and O, are duplicated, the number of distinct permutations is one fourth of that, or 1260.
How many permutation are possible of the letters in the word numbers?
The word "numbers" consists of 7 distinct letters. The number of permutations of these letters is calculated using the factorial of the number of letters, which is 7!. Therefore, the total number of permutations is 7! = 5,040.
What are the distinct letters from MISSISSIPI?
The distinct letters in the word "MISSISSIPPI" are M, I, S, and P. There are four unique letters in total.
How many ways are there to arrange the letters in the word ADDRESS if the two Ds must be together?
The permutations of the letters ADDRESS if the two D's must be together is the same as the permutations of the letters ADRESS, which is 6 factorial, or 720, divided by 2, to compensate for the two S's, which means that the number of distinct permutations of the letters ADDRESS, where the two DD's must be together is 360.
Question 4 how many different permutations of the letters in the word Mississippi are there?
There are 11!/(4!*4!*2!) = 34,650 ways.
What are distinct letters of Mississippi?
MS is the U.S. Postal Service abbreviation for the state of Mississippi. Miss. also is used as an abbreviation for Mississippi.
How many arrangements can be made with the letters spineless?
The word "spineless" has 9 letters, including 3 s's and 2 e's, so the number of distinct permutations of the letters is: 9!/(3!2!) = 30,240
How do you calculate distinguishable permutations?
The number of permutations of n distinct objects is n! = 1*2*3* ... *n. If a set contains n objects, but k of them are identical (non-distinguishable), then the number of distinct permutations is n!/k!. If the n objects contains j of them of one type, k of another, then there are n!/(j!*k!). The above pattern can be extended. For example, to calculate the number of distinct permutations of the letters of "statistics": Total number of letters: 10 Number of s: 3 Number of t: 3 Number of i: 2 So the answer is 10!/(3!*3!*2!) = 50400
