Their are two cases when this might occur.
Case 1: The three numbers you have are all the same number. This is pretty self exlanatory... but ill show an example
99+99+99/3=99
35+35+35/3=35
1056+1056+1056/3=1056
Case 2: You have one number that is exactly in the center of two other numbers. In other words this means that you have one number lets call it X then another number lets call it Y is a certain amount of units above number X. Then you have another number lets called this Z that is the same amount of units below X. Let me show you a few examples.
34+40+46/3 = 40 (In this case Z and Y are 6 units above and below X)
98+136+174/3 = 136 (In this case Z and Y are 38 units above and below X)
Yes. For example, the average of 5, 7, and 9 is 7.
Oh, what a lovely question! To find the average of those numbers, you simply add them all together and then divide by how many numbers there are. So, for 6, 7, and 8, you would add them (6 + 7 + 8 = 21) and then divide by 3 (since there are 3 numbers), giving you an average of 7.
The average of these three numbers is 10.666
The average of these three numbers is 12.
It average of 2 numbers is 9 then take 9 away from 12, so average of 3 numbers is now 9, with 3 'left over.' The 3 which is 'left over' divides among the three numbers by adding 1 to each of them, raising the new average to 10.
Yes. For example, the average of 5, 7, and 9 is 7.
Absolutely! There are many, many other examples but the most obvious is any three consecutive numbers - take 7, 8 & 9. To find the average we add them up (24) and divide by 3 = 8. In fact, as long as the "distance" between the 1st and 2nd number is the same as between the 2nd & 3rd number, the average will always equal the 2nd number.
Yes. For example, the average of 9, 10, and 11 is 10. 9 + 10 + 11 = 30 30 / 3 = 10
The average of three numbers which sum to 66 is 66/3 = 22. If 22 is the sum of three consecutive integers, then those three integers are 21,22,23. Kermit Rose
To calculate the average of two numbers, add them together, and divide the result by 2. (For the average of three numbers, you add up the three numbers, and divide by three, etc.) The average is (5000 + 7000)/2 = 6000
125, 126 and 127.
3, 5, and 7 are three prime numbers whose average is 5.
The average of the numbers 51, 52, and 56 is 53. To get the average you would add all three numbers and then divide by three.
12
I honestly don't know how to work out averages on a calculator, but I do know to get a average you need to add up all the numbers and then divide by how many there are .. maybe that's what your looking for. In this example we will say there are three numbers 1,2,3 you add all those numbers up (1,2,3) and then you divide by three since there are three numbers and then that's your average. Example: 1+2+3/3 (One plus two plus three divided by three)
3, 5, and 7 are three prime numbers whose average is 5.
Oh, what a lovely question! To find the average of those numbers, you simply add them all together and then divide by how many numbers there are. So, for 6, 7, and 8, you would add them (6 + 7 + 8 = 21) and then divide by 3 (since there are 3 numbers), giving you an average of 7.