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Their are two cases when this might occur.
Case 1: The three numbers you have are all the same number. This is pretty self exlanatory... but ill show an example
99+99+99/3=99
35+35+35/3=35
1056+1056+1056/3=1056
Case 2: You have one number that is exactly in the center of two other numbers. In other words this means that you have one number lets call it X then another number lets call it Y is a certain amount of units above number X. Then you have another number lets called this Z that is the same amount of units below X. Let me show you a few examples.
34+40+46/3 = 40 (In this case Z and Y are 6 units above and below X)
98+136+174/3 = 136 (In this case Z and Y are 38 units above and below X)
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Could an average of three numbers be one of those three numbers?
Yes. For example, the average of 5, 7, and 9 is 7.
What is the average of the numbers 6 7 and 8?
Oh, what a lovely question! To find the average of those numbers, you simply add them all together and then divide by how many numbers there are. So, for 6, 7, and 8, you would add them (6 + 7 + 8 = 21) and then divide by 3 (since there are 3 numbers), giving you an average of 7.
What is the the average of 12 17 and 7?
The average of these three numbers is 12.
What is the average of 9 11 12?
The average of these three numbers is 10.666
Average of two numbers is 9 If the third numbers is 12 than what is the average of this three numbers?
It average of 2 numbers is 9 then take 9 away from 12, so average of 3 numbers is now 9, with 3 'left over.' The 3 which is 'left over' divides among the three numbers by adding 1 to each of them, raising the new average to 10.
