Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.
When a linear equation is in the form
y = mx + b,
m is the slope, and b is the y-intercept. So, for example,
y = (2/3)x + 5
is perpendicular to
y = (-3/2)x + 7.
(The y-intercepts in these two equations are random numbers.)
"Y = any number" is perpendicular to "x = -3".
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
y = x
It would be perpendicular to a line with the equation Y = 1/8 X.
Yes, I could, if I knew the slope of the line given.
write a perpendicular 8 and u will get your answer
"Y = any number" is perpendicular to "x = -3".
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
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If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
If you mean: y = -2x -2 and point of (2, 3)Then perpendicular equation is: y-3 =1/2(x-2) => 2y = x+4
-3x+9=y
y = -x + 6
y = x
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
It would be perpendicular to a line with the equation Y = 1/8 X.