Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.
When a linear equation is in the form
y = mx + b,
m is the slope, and b is the y-intercept. So, for example,
y = (2/3)x + 5
is perpendicular to
y = (-3/2)x + 7.
(The y-intercepts in these two equations are random numbers.)
"Y = any number" is perpendicular to "x = -3".
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
To write an equation for a perpendicular line, first determine the slope of the original line. If the slope of the original line is ( m ), the slope of the perpendicular line will be the negative reciprocal, ( -\frac{1}{m} ). Using the point-slope form ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is a point on the new line, substitute the perpendicular slope and point to derive the equation of the perpendicular line. Finally, you can rearrange it into slope-intercept form, ( y = mx + b ), if desired.
y = x
To write an equation that is part one parallel and part two perpendicular to a given line, start by identifying the slope of the original line from its equation, typically in the form (y = mx + b), where (m) is the slope. For the parallel part, use the same slope (m) for the new equation, resulting in the form (y = mx + b_1), where (b_1) is a different y-intercept. For the perpendicular part, use the negative reciprocal of the original slope, (-\frac{1}{m}), leading to the equation (y = -\frac{1}{m}x + b_2), with (b_2) being another y-intercept.
write a perpendicular 8 and u will get your answer
"Y = any number" is perpendicular to "x = -3".
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
15
To write an equation for a perpendicular line, first determine the slope of the original line. If the slope of the original line is ( m ), the slope of the perpendicular line will be the negative reciprocal, ( -\frac{1}{m} ). Using the point-slope form ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is a point on the new line, substitute the perpendicular slope and point to derive the equation of the perpendicular line. Finally, you can rearrange it into slope-intercept form, ( y = mx + b ), if desired.
If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
If you mean: y = -2x -2 and point of (2, 3)Then perpendicular equation is: y-3 =1/2(x-2) => 2y = x+4
y = -x + 6
-3x+9=y
y = x
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.