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Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.
When a linear equation is in the form
y = mx + b,
m is the slope, and b is the y-intercept. So, for example,
y = (2/3)x + 5
is perpendicular to
y = (-3/2)x + 7.
(The y-intercepts in these two equations are random numbers.)
What else can I help you with?
Write an equation of the line that is perpendicular to x equals -3?
"Y = any number" is perpendicular to "x = -3".
How do you write the equation for a perpendicular line?
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
How do you write a equation for slope 1 y-intercept 0 perpendicular slope -1 y equals -x?
y = x
How do you write an equation that is part one parallel and then also part two perpendicular to the equation?
To write an equation that is part one parallel and part two perpendicular to a given line, start by identifying the slope of the original line from its equation, typically in the form (y = mx + b), where (m) is the slope. For the parallel part, use the same slope (m) for the new equation, resulting in the form (y = mx + b_1), where (b_1) is a different y-intercept. For the perpendicular part, use the negative reciprocal of the original slope, (-\frac{1}{m}), leading to the equation (y = -\frac{1}{m}x + b_2), with (b_2) being another y-intercept.
The line given by the equation y equals -8x is perpendicular to what line?
It would be perpendicular to a line with the equation Y = 1/8 X.
What is the longest math equation ever?
write a perpendicular 8 and u will get your answer
Write an equation of the line that is perpendicular to x equals -3?
"Y = any number" is perpendicular to "x = -3".
How do you write the equation for a perpendicular line?
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
Write an equation of a line that is perpendicular to y equals 3x-12?
15
How do you Write the equation of the line that is perpendicular to y 3x plus 8 and passes through the point (-3 4).?
If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
How do I write an equation in slope-intercept form for a line perpendicular to the graph of the equation that passes through the x-intercept of that line?
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
Write the equation of the line through (2 3) that is perpendicular to y -2x - 2.?
If you mean: y = -2x -2 and point of (2, 3)Then perpendicular equation is: y-3 =1/2(x-2) => 2y = x+4
Write the equation of the line that has a y-intercept of 0-9 and is perpendicular to the line 3x - 9y 8?
-3x+9=y
Write the equation of a line perpendicular to the line y x - 3 and containing the point 8 -2?
y = -x + 6
How do you write a equation for slope 1 y-intercept 0 perpendicular slope -1 y equals -x?
y = x
Can you write the equation of a line with one point on the line?
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
How do you write an equation that is part one parallel and then also part two perpendicular to the equation?
To write an equation that is part one parallel and part two perpendicular to a given line, start by identifying the slope of the original line from its equation, typically in the form (y = mx + b), where (m) is the slope. For the parallel part, use the same slope (m) for the new equation, resulting in the form (y = mx + b_1), where (b_1) is a different y-intercept. For the perpendicular part, use the negative reciprocal of the original slope, (-\frac{1}{m}), leading to the equation (y = -\frac{1}{m}x + b_2), with (b_2) being another y-intercept.
