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If you mean x squared + 9, you differentiate this as follows:
Use the differentiation formula for a power, to differentiate the x squared.
Separately, use the differentiation formula for a constant, to differentiate the 9.
Finally, use the differentiation formula for a sum to add up the parts.
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What is the differentiation of 'sin 4x'?
d/dx[sin(4x)] = sin(4x) ======
How to differentiate x plus 2?
d/dx(x + 2) = d/dx(x) + d/dx(2) = 1 + 0 = 1
Why is the rate of chage 0?
I assume you are asking about using differentiation. In this case, where dy-by-dx=0, there is a stationary point on the graph i.e. where the gradient is equal to 0.
How do you differentiate exp exp x?
Use the "chain rule" of differentiation: y=exp(exp(x)) taking ln both side in y=e x (1/y)dy/dx=e x dy/dx=y*e x dy/dx=exp(x+exp(x))
Calculate dy over dx when xy3 squared plus y equals 3x?
Calculate dx when xy3 + y = 3x.
What the differentiation and anti-differentiation formula?
There is no single formula for differentiation and anti-differentiation.The deriviative of a function y = f(x) is the limit of delta y over delta x as delta x approaches zero.OR:If f(x)=axn,f'(x)=(an)xn-1The deriviative of 2x3 would be 6x2.The anti-deriviative of a function is the reverse operation, i.e. the function is the deriviative of the anti-deriviative.Anti differentiation introduction:Anti differentiation is also called as integration process. It gives the reverse value of the differentiation equation. Anti differentiation is also called as anti derivative of the function. In this anti differentiation, f(x) is anti derivative of the function F(x). Anti differentiation is used for finding the area of the region under the certain curve. Anti differentiation symbol is denoted as ∫.General formula for anti differentiation:∫ xn dx = [xn + 1 / (n + 1)]+ c∫ k dx = k ∫ dx∫ udv = uv - ∫ v du∫ (w + y) dx = ∫ w dx + ∫ y dxanti-differentiation
What is the differentiation of 'sin 4x'?
d/dx[sin(4x)] = sin(4x) ======
How to differentiate x plus 2?
d/dx(x + 2) = d/dx(x) + d/dx(2) = 1 + 0 = 1
Why is the rate of chage 0?
I assume you are asking about using differentiation. In this case, where dy-by-dx=0, there is a stationary point on the graph i.e. where the gradient is equal to 0.
How do you differentiate exp exp x?
Use the "chain rule" of differentiation: y=exp(exp(x)) taking ln both side in y=e x (1/y)dy/dx=e x dy/dx=y*e x dy/dx=exp(x+exp(x))
Calculate dy over dx when xy3 squared plus y equals 3x?
Calculate dx when xy3 + y = 3x.
What is the differentiation of y with respect to x for x equals y exponent y?
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
How do you find the definition of derivative of f of x equals 3x plus 2?
The definition of the derivative, at a point X = x is the limit, as dx tends to 0, of [f(x+dx)-f(x)]/dx. In this case, therefore, it is lim[3*(x+dx)+2 - (3*x+2)]/dx = lim[3x + 3*dx +2 - 3x - 2]/dx = lim[3*dx/dx] = lim[3] = 3.
How do you find the rate of change?
Differentiation of the function would give you an instantaneous rate of change at one point; the tangent line. Repeated differentiation of some functions would give you many such points. f(x) = X3 = d/dx( X3) = 3X2 =======graph and see
What is johnathan coachman's entrance song?
dx dx dx dx dx dx dx dx dx dx dx dx dx dx dx dx dx d dx dx dx dx dx dx dx dx
What is the derivative of xy-2y equals 1?
by implicit differentiation you have y+x*dy/dx-2dy/dx=0 solving for dy/dx you'll have dy/dx=y/(2-x) and solving for y in the original equation and plugging it back in, you'll get dy/dx=1/(-x^2 +4x-4) which is your final answer
What is the derivative of 2x2 plus 3x plus 7?
d/dx 2x2+3x+7=4x+3
