d/dx[sin(4x)]
= sin(4x)
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-x*4*cos4x + (-1)*sin4x = -4xcos(4x) - sin(4x)
The differentiation of sin x plus cosx is cos (x)-sin(x).
The problem is If y³−3y+4x=0, find y′ by implicit differentiation
to find sin 35 here we take the angle = x=15 then 3x=45 , 4x=60 then 4x-3x=60-45 then by putting sin on rhs we will get cos 35 and sin 35 hope it helped you
(1/8)(x-sin 4x)