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MN^5/p^4

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Q: Divide M2n3 over p3 by mp over n2?
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Divide m2n3 over p3 by mp over n2 equals?

The expression m^2n^3/p^3 divided by mp/n^2 can be simplified as (m^2n^3/p^3) / (mp/n^2). This simplifies to (m^3n^5)/(p^3n) = m^3n^4/p^3.


What is the Derivative of y equals k multiplited by N divide 1 plus N2 where k is a constant?

y = kn / (1 + n2)First, let's express it with negative exponents:y = kn * (1 + n2)-1Then apply the chain rule:dy|dn = k(1 + n2)-1 - kn(1 + n2)-2 * 2nAnd simplify:dy|dn = k / (1 + n2) - 2n / kn(1 + n2)


Four times the square of a number is 16?

4*n2 = 16 Divide both sides by 4: n2 = 4 Take square roots: n = -2 or n = 2


How many moles of N2 are in 50g of it?

To determine the number of moles of N2 in 50g, you first need to find the molar mass of N2 (28.02 g/mol). Then, you divide the given mass (50g) by the molar mass to get the number of moles. In this case, 50g / 28.02 g/mol ≈ 1.79 moles of N2.


What is the majority of air on Earth?

Nitrogen (N2) at a little over 78%


What is the value of n when 6 over n times 5 over n-1 equals 1 over 3 showing all work?

If you mean: 6/n times 5/n-1 = 1/3 Then: 30/n2-n = 1/3 Multiplying both sides by n2-n: 30 = n2-n/3 Multiplying both sides by 3: 90 = n2-n Subtracting 90 from both sides: 0 = n2-n-90 or n2-n-90 = 0 Solving the above quadratic equation: n = -9 or n =10 If n is of a material value its more likely to be 10 Note that n2 means n squared


Are there infinitely many primes of the form n2-1 and n2-2 and n2-3 and n2-4?

n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.


3n2-7 equals 0 qaudratic form?

Add 7 to each side: 3n2 = 7 Divide each side by 3: n2 = 7/3 n = sqrt 7/sqrt 3, ie just over 1.5


What is the pmf of trinomial distribution?

P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n


What is the oxidation number for N2?

0 in N2


What is oxidation number for N2?

0 in N2


What is n2 in math?

n x n = n2