Yes, these measurements work for a right triangle.
7^2 + 24^2 = 25^2
Good luck. :-)
Yes... but not of the same right triangle. A right triangle's side lengths a, b, and c must satisfy the equation a2 + b2 = c2.
right angle triangle
No because the given lengths don't comply with Pythagoras' theorem for a right angle triangle.
No because the given sides do not comply with Pythagoras' theorem for a right angle triangle.
To determine if the side lengths of 4m, 5m, and 7m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the longest side (hypotenuse) equals the sum of the squares of the other two sides. Here, 7m is the longest side. Calculating, (4^2 + 5^2 = 16 + 25 = 41) and (7^2 = 49). Since (41 \neq 49), these side lengths cannot form a right triangle.
If its a right angle triangle then its side lengths could be 3, 4 and 5
Yes... but not of the same right triangle. A right triangle's side lengths a, b, and c must satisfy the equation a2 + b2 = c2.
right angle triangle
No because the given lengths don't comply with Pythagoras' theorem for a right angle triangle.
no.
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Yes, an isosceles triangle with two size lengths of 3 and one of 8 :)
No because the given sides do not comply with Pythagoras' theorem for a right angle triangle.
That depends on what the side lengths are. Until the side lengths are known, the triangle can only be classified as a triangle.
There are not any following lengths in the question to compare. Using the sizes given, and Pythagorean Theorem, the Hypotenuse of the triangle is 36.76 - which will have to do!
There can be no tangent side. The tangent of an angle, in a right angled triangle, is a ratio of the lengths of two sides.
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