No, two-dimensional shapes do not have faces in the way three-dimensional objects do. Faces are flat surfaces that make up the boundaries of 3D shapes. In contrast, 2D shapes, such as squares or circles, have only length and width, existing on a single plane without depth.
A polyhedron.
Such a shape cannot exist in ordinary 3 dimensional space.
They are closed 3-dimensional shapes with polygonal faces.
A rhombus is a two dimensional figure while the concept of {faces, vertices and edges} is relevant to 3-dimensional shapes.
They are both 3 dimensional shapes with faces that are polygons.
No, two dimensional shapes do not have faces
a cone
A polyhedron.
Bases are faces but faces are not necessarily bases.
No. A sphere is a three dimensional shape which has no polygonal faces. Similarly an ellipsoid, a torus, a paraboloid, hyperboloid etc are 3-D shapes with no polygonal faces.
Such a shape cannot exist in ordinary 3 dimensional space.
They are closed 3-dimensional shapes with polygonal faces.
triangular pyramaid
A three dimensional shape bounded by plane (flat) faces is a polyhedron.
the answer really is 6there are 6 faces in a three-dimensional model
This question is faulty. Only 2-dimensional shapes can have their sides counted. For a 3-dimensional shape, you must count either edges or faces.
Any 2-dimensional shape has a vertex where two sides meet.Any 3-dimensional shape has a vertex where three or more faces meet.