A polyhedron.
Such a shape cannot exist in ordinary 3 dimensional space.
They are closed 3-dimensional shapes with polygonal faces.
A rhombus is a two dimensional figure while the concept of {faces, vertices and edges} is relevant to 3-dimensional shapes.
They are both 3 dimensional shapes with faces that are polygons.
No, two dimensional shapes do not have faces
a cone
A polyhedron.
Bases are faces but faces are not necessarily bases.
No. A sphere is a three dimensional shape which has no polygonal faces. Similarly an ellipsoid, a torus, a paraboloid, hyperboloid etc are 3-D shapes with no polygonal faces.
Such a shape cannot exist in ordinary 3 dimensional space.
They are closed 3-dimensional shapes with polygonal faces.
triangular pyramaid
A three dimensional shape bounded by plane (flat) faces is a polyhedron.
the answer really is 6there are 6 faces in a three-dimensional model
This question is faulty. Only 2-dimensional shapes can have their sides counted. For a 3-dimensional shape, you must count either edges or faces.
Any 2-dimensional shape has a vertex where two sides meet.Any 3-dimensional shape has a vertex where three or more faces meet.