To maximize the area of a rectangular dog pen with 52 feet of Fencing, you can set up the equation for the perimeter: (2x + 2y = 52), which simplifies to (x + y = 26). The area (A) can be expressed as (A = x \cdot y), where (y = 26 - x). Substituting gives (A = x(26 - x) = 26x - x^2). This is a quadratic function that reaches its maximum when (x = 13) feet, making the width that maximizes the area 13 feet.
625 sq feet.
36
That would probably be a 25x25 square with an area of 625 square feet.
18 meters of fencing. You simply need to find the circumference of the rectangle.
To enclose a rectangular garden, you need to calculate the perimeter. The perimeter ( P ) is given by the formula ( P = 2 \times (length + width) ). For a garden that is 14 feet wide and 20 feet long, the calculation is ( P = 2 \times (20 + 14) = 2 \times 34 = 68 ) feet. Therefore, 68 feet of rope is needed to enclose the garden.
625 sq feet.
101
36
832 yards
That would probably be a 25x25 square with an area of 625 square feet.
A rectangular lot that's 150-ft wide has to be 290.4-ftlongin order to enclose exactly 1 acre.
a veterinarian uses 600 feet of chain-link fence to enclose a rectangular region. It is subdivided evenly into two smaller rectangles by placing fence parallel to one of the sides. what is the width (w) as a function of the length (L)? (w=?) what is the total area as a function of (L)? (A=?) what are the dimensions that produce the greatest enclosed area? EXPLENATION PLEASE
46 feet of fence. Add all the sides together.
625 square feet.. the area would be a square rectangle with 25 feet of fencing on each side.
18 meters of fencing. You simply need to find the circumference of the rectangle.
I got no clue.
50' x 50'and its spelled dimension not demension