101
46 feet of fence. Add all the sides together.
width=x length=y 2y + 2x = 22 y= 2x+2 2(2x+2) + 2x= 22 4x + 4 +2x = 22 6x=18 x=3 y=2(3) + 2 y=8 Length=8 Width=3
the length of a rectangular garden is 2 feet longer than 3 times it's width .if the perimeter of the garden is 100 feet find the width and length of the garden
The area of a rectangular garden is length * width. You have 200 = Length * 20, and so Length = 10 metres. Conventionally, for a rectangle, the length is the longer of the two dimensions, though for a garden, it is often the distance from the back of the house to the end of the garden that is referred to as the length - even if it is the shorter dimension.
Length of rectangle garden is 5 m greater than the width. the area is 84 m2. find the dimensions of the garden.
625 sq feet.
36
The dimensions are 12 feet by 4 feet
What do you mean by "largest" ??? Do you want the widest rectangle ? The longest rectangle ? How about the rectangle with the most area ? The length can be anything less than 20 ft, and the width can be anything less than 20 ft. Any of those shapes will have an area greater than zero. The rectangular garden with the greatest possible area is a square, 10 ft x 10 ft. Its area is 100 square feet.
66' x 3.27'
46 feet of fence. Add all the sides together.
9 x 8
divide perimeter by 6.
To enclose a rectangular garden, you need to calculate the perimeter. The perimeter ( P ) is given by the formula ( P = 2 \times (length + width) ). For a garden that is 14 feet wide and 20 feet long, the calculation is ( P = 2 \times (20 + 14) = 2 \times 34 = 68 ) feet. Therefore, 68 feet of rope is needed to enclose the garden.
The answer depends on the dimensions of the garden as well as how wide the fence panels are. Without the information, it is pointless to try and answer the question.
length = 22 meters and width = 6 meters
The greatest possible area is 90 square feet.