No,
A+B is left as A+B
AB would be A x B
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That factors to (a + 1)(a + b) a = -1, -b b = -a
ab=1a+1b a is equal to either 0 or two, and b is equal to a
If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.
(a-2(ab)1/2+b)/(a-b)
Commutativity.