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Interior angles of a 40-gon?
The sum of the interior angles of an n-gon is (n-2)*180 degrees. So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees. If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.
What is the number of sides of a regular polygon if one angle measures 171 degrees?
The formula to find the sum of the angles of a polygon is: 180(n - 2) Since we know that one angle of this regular polygon is 171 degrees, we can find what kind of polygon it will be, using the formula: 180(n - 2) = 171n 180n - 360 = 171n 180n - 171n = 360 9n = 360 n = 360/9 n = 40 Thus the polygon is a 40-sided polygon. Check: 180(40 - 2) = 180(38) = 6840, which is the sum of the angles of the polygon. 6840/40 = 171 degrees, which is the measure of one of the angles of that polygon .
How many times does 45 go into 6840?
To find out how many times 45 goes into 6840, you would divide 6840 by 45. The result of this division is 152, meaning that 45 goes into 6840 152 times. This is because 45 multiplied by 152 equals 6840.
What percent is 6840 out of 38000?
(try to simplify the fraction first) 6840/38000 = 684/3800 = 18/100 = 18 %
What are common multiples of 360?
It depends upon the other number(s) with which 360 has COMMON multiples; it will be a subset of the multiples of 360, that is a subset of:360, 720, 1080, 1440, 1800, 2160, 2520, 2880, 3240, 3600, 3960, 4320, 4680, 5040, 5400, 5760, 6120, 6480, 6840, 7200, 7560, 7920, 8280, 8640, 9000, 9360, 9720, 10080, 10440, 10800, 11160, 11520, 11880, 12240, 12600, 12960, 13320, 13680, 14040, 14400, 14760, 15120, 15480, 15840, 16200, 16560, 16920, 17280, 17640, 18000, 18360, 18720, 19080, 19440, 19800, 20160, 20520, 20880, 21240, 21600, 21960, 22320, 22680, 23040, 23400, 23760, 24120, 24480, 24840, 25200, 25560, 25920, 26280, 26640, 27000, 27360, 27720, 28080, 28440, 28800, 29160, 29520, 29880, 30240, 30600, 30960, 31320, 31680, 32040, 32400, 32760, 33120, 33480, 33840, 34200, 34560, 34920, 35280, 35640, 36000, ...
How many sides does a polygon have when the interior angles add up to 6840?
There are: (6840+360)/180 = 40 sides
If the sum of the interior angles of a polygon is 6840 how many sides does it have?
sum interior angles = (number of side - 2) × 180° → number of sides = sum interior angles ÷ 180° + 2 = 6840° ÷ 180° + 2 = 40 It has 40 sides.
What are the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of a polygon can be calculated using the formula: [ \text{Sum of interior angles} = (n - 2) \times 180^\circ ] where (n) is the number of sides of the polygon. For a polygon with 40 sides ((n = 40)): [ \text{Sum of interior angles} = (40 - 2) \times 180^\circ = 38 \times 180^\circ = 6840^\circ ] Thus, the sum of the interior angles of a polygon with 40 sides is **6840 degrees Read more....tinyurl com/22enuvst
What is the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 6840 degrees
What is the interior of a 40 side polygon?
The interior angles of a 40 sided polygon add up to 6840 degrees
What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
What is the total measure of the angles of a forty sided polygon?
Exterior angles add up to 360 degrees Interior angles add up to 6840 degrees
Interior angles of a 40-gon?
The sum of the interior angles of an n-gon is (n-2)*180 degrees. So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees. If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.
What is the number of sides of a regular polygon if one angle measures 171 degrees?
The formula to find the sum of the angles of a polygon is: 180(n - 2) Since we know that one angle of this regular polygon is 171 degrees, we can find what kind of polygon it will be, using the formula: 180(n - 2) = 171n 180n - 360 = 171n 180n - 171n = 360 9n = 360 n = 360/9 n = 40 Thus the polygon is a 40-sided polygon. Check: 180(40 - 2) = 180(38) = 6840, which is the sum of the angles of the polygon. 6840/40 = 171 degrees, which is the measure of one of the angles of that polygon .
Does a 40 sided polygon have 6840 diagonals?
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
What is the sum of the interior of a 40 gon?
6840 degrees
How many times does 45 go into 6840?
To find out how many times 45 goes into 6840, you would divide 6840 by 45. The result of this division is 152, meaning that 45 goes into 6840 152 times. This is because 45 multiplied by 152 equals 6840.
