The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
tetracontahedron
40-gon.
I find the name "30-sided polygon", "40-sided polygon", etc. just fine.
A 40 sided polygon is call a Tetracontagon. Try saying that ten times fast. :) Hope this helped.
0.5*(402-120) = 740 diagonals
It has 40 diagonals.Improved Answer:-Using the formula for diagonals of a polygon: 0.5*(442-132) = 902 diagonals
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
A 40-sided polygon has 40 sides. Count again, to be sure.
The name of a 40 sided polygon is Tetracontagon.
tetracontahedron
If its a regular 9 sided polygon then the exterior angles are 40 degrees.
It is called Tetracontagon.
40-gon.
The interior angles of a 40 sided polygon add up to 6840 degrees
I find the name "30-sided polygon", "40-sided polygon", etc. just fine.
The sum of the interior angles of a convex polygon with n sides is given by (n-2)x180o. So for a 40 sided polygon n=40; thus (40-2)x180o = 38x180o = 6840o.