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In a magic square, the magic number (or magic constant) can be calculated using the formula ( M = \frac{n(n^2 + 1)}{2} ), where ( n ) is the order of the square. For a 3x3 magic square (where ( n = 3 )), the magic number is ( M = \frac{3(3^2 + 1)}{2} = 15 ). Since the center number is 8, the remaining numbers in the square must be arranged such that each row, column, and diagonal sums to 15.

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The square of the number 8 is?

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