7
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
The equation 3m - 3m - 7 = 0, simplifies to -7 = 0 this means that the the solution is no solution, since -7 doesn't equal 0.
1st equation: 5x +7y +29 = 0 or 5x +7y = -29 2nd equation: 11x -3y -65 = 0 or 11x -3y = 65 Times all terms in the 1st equation by 11: 55x +77y = -319 Times all terms in 2nd equation by 5: 55x -15y = 325 Subtract the 2nd equation from the 1st equation: 92y = -644 or y = -7 By means of substitution point of intersection is made at: (4, -7)
The exclamation point in a math equation symbolizes the factorial function. The factorial of an integer > 0 is the product of that integer and all of the integers between 1 and that integer. For instance 7! is 7 * 6 * 5 * 4 * 3 * 2 * 1, or 5040. The special case of 0! is defined as 1.
When you graph the equation [ y = 7x ], the graph is a straight line that passes throughthe origin and has a slope of 7.The x-y coordinates of every point on the line are an ordered pair that satisfies the equation.There are as many of them as there are points on a line ... an infinite number.Here are a few of them:(0, 0)(1, 7)(0.2, 1.4)(-9, -63)(137, 959)
7
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
No.No.No.No.
The ordered pair (0, -6) Ordered pairs look like (x, y). they are the coordinates of a point on your graph. Asking if (0,6) is a solution to your equation means, does this point lie on the graph? Or algebraically, if you substitute in x = 0 and y = -6 into the equation, does it work? y = 5x-7 -6 = 5(0) -7 -6 = 0 - 7 -6 = -7 Well, -6 does NOT = -7, so we know that this ordered pair is not a solution to the function.
The equation 3m - 3m - 7 = 0, simplifies to -7 = 0 this means that the the solution is no solution, since -7 doesn't equal 0.
Points: (7, 0) and (0, 11) Slope: 0-11/7-0 = -11/7 Equation: y-0 = -11/7(x-7) => 7y = -11x+77 Equation: y-11 = -11/7(x-0) => 7y = -11x+77
1st equation: 5x +7y +29 = 0 or 5x +7y = -29 2nd equation: 11x -3y -65 = 0 or 11x -3y = 65 Times all terms in the 1st equation by 11: 55x +77y = -319 Times all terms in 2nd equation by 5: 55x -15y = 325 Subtract the 2nd equation from the 1st equation: 92y = -644 or y = -7 By means of substitution point of intersection is made at: (4, -7)
Point: (7, -5) Slope: -4/7 Equation: 7y = -4x-7
The exclamation point in a math equation symbolizes the factorial function. The factorial of an integer > 0 is the product of that integer and all of the integers between 1 and that integer. For instance 7! is 7 * 6 * 5 * 4 * 3 * 2 * 1, or 5040. The special case of 0! is defined as 1.
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement
5x2 + 12x + 7 = 0 This equation can be factored : (5x + 7) (x + 1) = 0 The equation equals zero when either 5x + 7 = 0 or x + 1 = 0 When 5x + 7 = 0 then 5x = -7 : x = -7/5 or -1.4 When x + 1 = 0 then x = -1 The solutions or roots of this equation are x = -7/5 and x = -1