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How do you find perimeterwhen the length and area is given?
take area and divide by length. this will give you width. take 2times width plus 2 times length and that is the perimeter
What is the length of a rectangle when the area is 6x2 plus 19x plus 10 and the width is 3x plus 2?
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
How do you find a area and perimeter of a room in square meters?
Measure it with a meter stick. Multiply the length times the width to find the area. Two times the length plus two times the width is the perimeter.
What is a formula for a perimeter and area of a rectangle and of a parallelagram?
Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]
A rectangle has a length 2 x - 4 and a width of x plus 5. What is the area of the rectangle in terms of x?
If x was equal to 5 then the length would be 6 and the width would be 10 making the area = to 60 units. A = (2x-4) * (x+5) = 2x2 - 4x + 10x -20 = 2x2 +6x -20
How do you find the area and perimeter of a rectangle?
Perimeter: Add the length of the four sides. Area: Multiply length x width.
Show a rectangle that has permeter and area?
The area is the length times the width. The perimeter is two times the length plus two times the width.
What is the area and perimeter of a shaded rectangle?
The area is the length times the width. The perimeter is two times the length plus two times the width.
How do you find perimeterwhen the length and area is given?
take area and divide by length. this will give you width. take 2times width plus 2 times length and that is the perimeter
What is the permeter and area ofthe shaded rectangle?
The area is the length times the width. The perimeter is two times the length plus two times the width.
If you know the perimeter and lenght of a rectangle and want to find its width do you divide the perimeter by the length?
No. If you draw a rectangle there are four sides, the length of two of those sides are equal to the length, and the other two are equal to the width. Therefore: the perimeter, which is equal to all the sides added up, is equal to two times the length plus two times the width: or 2L+2W= Perimeter. If you know L and you know the perimeter you can solve it algebraically. the width equals the perimeter minus two times the length, all that divided by two, or W= (P-2L)/2 (when you do the algebra). you might be thinking about the area in which case if you knew the area and the length and you want to find the width you would divide the area by the length.
Formula for surface area of a pyramid?
The surface area is length times width plus length. Then you find the square root of the width divided by two and then squared. You add this to the height squared plus the width. The width is multiplied by the square root of 1/2 squared plus the height squared.
What does length plus length plus width plus width equals?
it equals LxL+WxW
What is the area of a rectangle with length 7 and width h plus 8?
56
What is the length of a rectangle when the area is 6x2 plus 19x plus 10 and the width is 3x plus 2?
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
If the area is x2 plus 5x cm2 and the width is x cm what is the length?
Area = length x width: so plug in the values you know.x2 +5x = (length) x (x) :now divide both sides by xx + 5 = length
What is the answer to this math problem The area of a rectangular computer screen is 4x2 plus 20x plus 16 The width of the screen is 2x plus 8 What is the length of the screen?
Area = 4x2 + 20x + 16 Width = 2x + 8 Length = ? To begin, we will factorise all the expressions Area = 4(x2 + 5x + 4) = 4(x+1)(x+4) Width = 2(x+4) Length = ? The formula for Area is given by: Area = Length . Width (A dot has been used to represent multiplication in the above formula so as not to confuse it with the variable x) Substituting in our expressions for Area and Width gives: 4(x+1)(x+4) = Length . 2(x+4) Dividing both sides by 2(x+4) to solve for Length gives an answer of: Length = 2(x+1) If you look at the width and the length expressions, the width is longer than the length (which shouldn't be possible). It is most likely a mistake in the question.
