26 x 999 x 263 ie 456,519,024 (assuming the letters I, O & Q are used and numbers start at 001.)
6
From 4 letters, you can create three-letter combinations by selecting any 3 letters from the 4 and arranging them. The number of ways to choose 3 letters from 4 is given by the combination formula ( \binom{4}{3} = 4 ). Each of these combinations can be arranged in ( 3! = 6 ) ways. Therefore, the total number of three-letter combinations is ( 4 \times 6 = 24 ).
Four combinations: tam ham mat hat Hope it helps (:!
Because there are 7 letters that don't repeat, 7X6X5X4=840 combinations. To give you an idea of how to solve the problem, if there had been 9 letters and you wanted to make combinations of 3 letters, you would multiply: 9X8X7=504
Starting with three different letters, six two-letter combinations can be made, if the order of the two letters is important. Only three combinations can be made if the order of the two letters is not important. Example: ABC AB AC BA BC CA CB - six variations But if (for your purposes) BA is the same as AB, Then there are only three: AB AC BC
3,124,550 possible combinations
6
From 4 letters, you can create three-letter combinations by selecting any 3 letters from the 4 and arranging them. The number of ways to choose 3 letters from 4 is given by the combination formula ( \binom{4}{3} = 4 ). Each of these combinations can be arranged in ( 3! = 6 ) ways. Therefore, the total number of three-letter combinations is ( 4 \times 6 = 24 ).
256 iThink * * * * * It depends on combinations of how many. There is 1 combination of 4 letters out of 4, 4 combinations of 3 letters out of 4, 6 combinations of 2 letters out of 4, 4 combinations of 1 letter out of 4. Than makes 15 (= 24-1) in all. Well below the 256 suggested by the previous answer.
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Four combinations: tam ham mat hat Hope it helps (:!
No is a word. On is a word.
Because there are 7 letters that don't repeat, 7X6X5X4=840 combinations. To give you an idea of how to solve the problem, if there had been 9 letters and you wanted to make combinations of 3 letters, you would multiply: 9X8X7=504
20
Starting with three different letters, six two-letter combinations can be made, if the order of the two letters is important. Only three combinations can be made if the order of the two letters is not important. Example: ABC AB AC BA BC CA CB - six variations But if (for your purposes) BA is the same as AB, Then there are only three: AB AC BC
The word is European.
Assuming you can have duplicate letters such as AAA, AAB etc... there are 26 x 26 x 26 combinations - which is a total of 17,576 permutations !