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How many possible alpha numeric combinations are there using all letters for 4 characters?
With a Latin alphabet of 26 letters and the 10 digits 0...9, and allowing for repeats, you get: 36^4 = 36 × 36 × 36 × 36 = 1,679,616 combinations. If you were to include both lower and upper case characters, the number of possible combinations goes up (due to 26 lower case letters + 26 upper case letters + 10 digits = 62 characters to choose from): 62^4 = 14,776,336.
How may possi le alpha numeric combinations are there using all letters for 5 characters?
There are only alphabetic combinations since there are no numeric characters in letters.The answer assumes thatyou mean the modern Roman alphabet,letters may not be repeatedupper case and lower case letters are considered to be the same,you did mean combinations and not permutations.Then the answer is 26C5 = 26*25*24*23*22/(5*4*3*2*1) = 65,780
What is the maximum number of different three letter palindromes you can make using any letter of the alphabet?
The maximum number of different three letter palindromes that can be made using any letter of the alphabet is 1 - that letter repeated 3 times. However, if you meant you can pick any letter for each letter of the palindrome, then: The first and last letters are the same and there is a choice of 26 letters for them; For each choice for the first (and last) letter, there is a choice of 26 letters for the second letter Making a total of 26 × 26 = 676 such three letter palindromes (where case of the letter does not matter).
How many possible unique alpha numeric combinations are there using all letters for 4 characters?
im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.
How many possible eight-character passwords can be created using only uppercase letters and numbers?
87400 combinations
