360= 23 times 45
23 x 33 = 216
To express 375 in index form, we first factor it into its prime components. The prime factorization of 375 is (3 \times 5^3). Therefore, in index form, 375 can be written as (3^1 \times 5^3).
Prime numbers don't factorize; they're already prime.
To express 375 in prime factor index form, first, factor it into its prime components. The prime factorization of 375 is (3 \times 5^3) because (375 = 3 \times 125) and (125 = 5^3). Therefore, the prime factor index form of 375 is (3^1 \times 5^3).
To express 375 in index form, we first find its prime factorization. The prime factorization of 375 is (3 \times 5^3). Therefore, in index form, 375 can be written as (3^1 \times 5^3).
23 x 33 = 216
2^2 x 3 x 5 = 60
840 = 23 x 3 x 5 x 7
Prime factors of 1080 are 23 33 5.
Prime numbers don't factorize; they're already prime.
This is the prime factorization of 80 in index form: 80 = 2 x 2 x 2 x 2 x 5 = 24 x 5
Oh honey, let me break it down for you. 160 can be expressed as 2^5 * 5^1. In index form, that would be written as 2^5 * 5. So there you have it, 160 expressed as a product of prime numbers in index form. Hope that clears things up for ya!
To express 375 in prime factor index form, first, factor it into its prime components. The prime factorization of 375 is (3 \times 5^3) because (375 = 3 \times 125) and (125 = 5^3). Therefore, the prime factor index form of 375 is (3^1 \times 5^3).
2^4 x 3 x 5
2^2 x 3 x 5
360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.