F(x)=[x^2]+1
So what is the question?
14x
f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).
that isn't a real question.
-2, 1.74 and 0.46
yup
F(x)=[x^2]+1
So what is the question?
14x
find f'(x) and f '(c)f(x) = (x^3-3x)(2x^2+3x+5
The zeros of f(x), a function of the variable x, are those values of x for which f(x) = 0. These are points at which the graph of f(x) crosses (or touches) the x-axis. Many functions will do so several times over the relevant domain and the values (of x) are the distinct zeros.
To write 2025000 in decimal form, you simply place a decimal point after the last digit from the right. So, 2025000 in decimal form is 2,025,000.
f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).
100 deg F = 37.77... deg F
F = ma Force (in Newtons) equals mass (in kilograms) times acceleration (in meters per second squared) In this case, 450 = 30a, so the accelerating is 15 meters per second squared
that isn't a real question.