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Since ( y ) varies inversely as ( x ), we can express this relationship as ( y = \frac{k}{x} ) for some constant ( k ). Given that ( y = 24 ) when ( x = 8 ), we can find ( k ) by substituting these values: ( 24 = \frac{k}{8} ) implies ( k = 192 ). Now, to find ( y ) when ( x = 4 ), we use the equation: ( y = \frac{192}{4} = 48 ). Thus, ( y ) is 48 when ( x ) is 4.
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If y varies inversely as x and y 24 when x 8 find y when x is 4.?
If ( y ) varies inversely as ( x ), this means ( y = \frac{k}{x} ) for some constant ( k ). Given that ( y = 24 ) when ( x = 8 ), we can find ( k ) by substituting these values: ( 24 = \frac{k}{8} ) which gives ( k = 192 ). Now, to find ( y ) when ( x = 4 ), we use the equation ( y = \frac{192}{4} ), resulting in ( y = 48 ).
If y varies inversely as x and y 2 when x 1 find x when y is 4.?
If ( y ) varies inversely as ( x ), we can express this relationship as ( y = \frac{k}{x} ) for some constant ( k ). Given that ( y = 2 ) when ( x = 1 ), we can find ( k ) by substituting these values: ( 2 = \frac{k}{1} ), so ( k = 2 ). Now, to find ( x ) when ( y = 4 ), we use the equation ( 4 = \frac{2}{x} ). Solving for ( x ), we get ( x = \frac{2}{4} = \frac{1}{2} ).
X varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies d?
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
Y y varies inversely as x x. If x x 3 then y y 4. Find y y when x x 7.?
Since ( y ) varies inversely as ( x ), we can express this relationship as ( y = \frac{k}{x} ), where ( k ) is a constant. Given that when ( x = 3 ), ( y = 4 ), we can find ( k ) by substituting these values: ( 4 = \frac{k}{3} ), which gives ( k = 12 ). Now, to find ( y ) when ( x = 7 ), we use the equation ( y = \frac{12}{7} ). Thus, ( y \approx 1.71 ).
X varies directly with y and inversely with z x equals 20 when y equals 8 and z equals 4 Find x when y equals 4 and z equals 8?
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
If y varies inversely as x and y equals 24 when x equals 8 find y when x is 4?
y is 12
If y varies inversely as x and y 24 when x 8 find y when x is 4.?
If ( y ) varies inversely as ( x ), this means ( y = \frac{k}{x} ) for some constant ( k ). Given that ( y = 24 ) when ( x = 8 ), we can find ( k ) by substituting these values: ( 24 = \frac{k}{8} ) which gives ( k = 192 ). Now, to find ( y ) when ( x = 4 ), we use the equation ( y = \frac{192}{4} ), resulting in ( y = 48 ).
If y varies inversely as the square of x and y equals 4 when x equals 5 find y when x is 2?
25
If y varies inversely as x and y 5 when x 2 find x when y is 4?
Since ( y ) varies inversely as ( x ), we can express this relationship as ( y = \frac{k}{x} ), where ( k ) is a constant. Given that ( y = 5 ) when ( x = 2 ), we can find ( k ) by substituting these values: ( 5 = \frac{k}{2} ), which gives ( k = 10 ). Now, to find ( x ) when ( y = 4 ), we set up the equation ( 4 = \frac{10}{x} ). Solving for ( x ) gives ( x = \frac{10}{4} = 2.5 ).
If y varies inversely as x and y 2 when x 1 find x when y is 4.?
If ( y ) varies inversely as ( x ), we can express this relationship as ( y = \frac{k}{x} ) for some constant ( k ). Given that ( y = 2 ) when ( x = 1 ), we can find ( k ) by substituting these values: ( 2 = \frac{k}{1} ), so ( k = 2 ). Now, to find ( x ) when ( y = 4 ), we use the equation ( 4 = \frac{2}{x} ). Solving for ( x ), we get ( x = \frac{2}{4} = \frac{1}{2} ).
X varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies d?
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
Y y varies inversely as x x. If x x 3 then y y 4. Find y y when x x 7.?
Since ( y ) varies inversely as ( x ), we can express this relationship as ( y = \frac{k}{x} ), where ( k ) is a constant. Given that when ( x = 3 ), ( y = 4 ), we can find ( k ) by substituting these values: ( 4 = \frac{k}{3} ), which gives ( k = 12 ). Now, to find ( y ) when ( x = 7 ), we use the equation ( y = \frac{12}{7} ). Thus, ( y \approx 1.71 ).
If y varies inversely as the square of x and y equals 4 when x equals 5 findy y when x is 2?
y varies inversely as x2 so y = c/x2 for some constant c. When x = 5, y = 4 So c = x2y = 100 that is y = 100/x2 Then, when x = 2, y = 100/4 = 25
E is inversely proportionnal to z and z equals 4 when E equals 6?
E = 24/z or, equivalently, z = 24/E
X varies directly with y and inversely with z x equals 20 when y equals 8 and z equals 4 Find x when y equals 4 and z equals 8?
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
If f x varies directly with x2 and f x 96 when x 4 find the value of f 2?
f(2) = 24.
Find 1 4 of 24?
1/4 of 24 = 24/4 = 6
