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X varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies d?
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
X varies directly with y and inversely with z x equals 20 when y equals 8 and z equals 4 Find x when y equals 4 and z equals 8?
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
If f x varies directly with x2 and f x 96 when x 4 find the value of f 2?
f(2) = 24.
How do you solve 1 fourth of 24?
1/4 of 24 = 1/4 x 24 = 1/4 x 24/1= (1x24)/(4x1) = 24/4 = 24 ÷ 4 = 6
How do you find 1 over 6 of 24?
1/6 x 24 = 4
If y varies inversely as x and y equals 24 when x equals 8 find y when x is 4?
y is 12
If y varies inversely as the square of x and y equals 4 when x equals 5 find y when x is 2?
25
X varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies d?
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
If y varies inversely as the square of x and y equals 4 when x equals 5 findy y when x is 2?
y varies inversely as x2 so y = c/x2 for some constant c. When x = 5, y = 4 So c = x2y = 100 that is y = 100/x2 Then, when x = 2, y = 100/4 = 25
X varies directly with y and inversely with z x equals 20 when y equals 8 and z equals 4 Find x when y equals 4 and z equals 8?
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
E is inversely proportionnal to z and z equals 4 when E equals 6?
E = 24/z or, equivalently, z = 24/E
If f x varies directly with x2 and f x 96 when x 4 find the value of f 2?
f(2) = 24.
Find 1 4 of 24?
1/4 of 24 = 24/4 = 6
Assume that y varies inversely with x and that y is 2 when x is 4 what is the equation of inverse variation?
2=8/4 the constant is 8 y-k/x i think.
What is it when Z varies directly with x and inversely with y When x 2 and y 4 z 3 What is the value of z when x 4 and y 9?
z = 8/3.
Complete the equation of variation where y varies inversely as x and y equals 4 when x equals 2?
xy = 8 or y = 8/x
How would you find the value of 24 by using the numbers 7 4 4 4?
(4 + 4) * (7 - 4) = 24 (7 - (4/4)) * 4 = 24
