0
What else can I help you with?
X varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies d?
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
X varies directly with y and inversely with z x equals 20 when y equals 8 and z equals 4 Find x when y equals 4 and z equals 8?
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
If x is inversely proportional to y and x is 60 when y is 0.5 find x when y is 12?
5/2
Find ( 1 ⅞ + 2¼) x 1⁵⁄11?
Find ( 1 ⅞ + 2¼) x 1⁵⁄
What does find the repirocal of each number mean?
Say, find the reciprocal of 2 = 1/2 Reciprocal of 1/2 = 2
If y varies inversely as the square of x and y equals 4 when x equals 5 find y when x is 2?
25
X varies directly with y and inversely with z x equals 0.12 when y equals 12 and z equals 2 Find x when y equals 1200 and z equals 1?
x = 24
X varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies directly with y and inversely with z. x 5 when y 10 and z 5. Find x when y 20 and z 10x varies d?
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
Assume that y varies inversely as x. If y equals -6 when x equals-2 find y when x equals 5?
-6/y=5/-2 5y=12 y=12/5
Complete the equation of variation where y varies inversely as x and y equals 80 when x equals 0.7?
2
What are Inverse Variation Equations?
The statement " y varies inversely as x means that when x increases, y decreases by the same factor.In other words, the expression xy is constant:xy = kwhere k is the constant of variation.We can also express the relationship between x and yas:y = k / xwhere k is the constant of variation.Example 1: If y varies inversely as x , and y = 6 when x = , write an equation describing this inverse variation.k = (6) = 8xy = 8 or y = 8 / ZThat's an example of an inverse variation!Example 2: If y varies inversely as x , and the constant of variation is k = , what is y when x = 10 ?xy =10y =y = × = × =k is constant. Thus, given any two points ( x 1, y 1 ) and ( x 2, y 2 ) which satisfy the inverse variation, x 1 y 1 = k and x 2 y 2 = k . Consequently, x 1 y 1 = x 2 y 2 for any two points that satisfy the inverse variation.Example 3: If y varies inversely as x , and y = 10 when x = 6 , then what is y when x = 15 ?x 1 y 1 = x 2 y 26(10) = 15y60 = 15yy = 4Thus, when x = 6 , y = 4 .Hope I helped!
If y varies inversely as the square of x and y equals 4 when x equals 3 find y when x is 2?
y varies as 1/x^(2) y = k X 1/^(2) y = k/x^(2) k = y x^(2) When y = 4 & x = 3 Then k = 4(3^(2)) k = 4(9) k = 36 (The constant of proportionality Hence the general equation is y = 36/x^(2) When x = 2 y = 36/2^(2) y = 36 /4 y = 9 The answer!!!!!
X varies directly with y and inversely with z x equals 20 when y equals 8 and z equals 4 Find x when y equals 4 and z equals 8?
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
If y varies inversely as the square of x and y equals 4 when x equals 5 findy y when x is 2?
y varies inversely as x2 so y = c/x2 for some constant c. When x = 5, y = 4 So c = x2y = 100 that is y = 100/x2 Then, when x = 2, y = 100/4 = 25
Assume that y varies inversely with x and that y is 2 when x is 4 what is the equation of inverse variation?
2=8/4 the constant is 8 y-k/x i think.
Complete the equation of variation where y varies inversely as x and y equals 4 when x equals 2?
xy = 8 or y = 8/x
Solve by using the steps found in this section. Write your answer in exact, simplified form y is inversely proportional to z. If y is when z is 15, find y when z is 30?
k = 2 Explanation: when z varies directly proportional to x means a division c = z x where c is a constant of proportionality when z varies inversely proportional to x it means a product z y = c now with both k = z y x z = 8 ; x = 12 and y = 3 k = 8.3 12 k = 2
