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Earn +20 ptsQ: Factor 4ac plus 2ad plus 2bc plus bd?
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Factor this expression 4ac plus 2ad plus 2bc plus bd?
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
How do you factor this expression 4ac plus 2ad plus 2bc plus bd?
(2a + b)(2c + d).
How do you factor 6x2-13x plus 15?
It cannot be factored because the discriminant of b2-4ac is less than zero.
B2 -4ac in the quadratic equation ax2 plus bx plus c equals 0?
Full equation is (-b +/- sqrt(b2 - 4ac))/2a. Try it with x2 - 2x - 3, where a = 1, b = -2 and c = -3...
2x² plus 5x plus 3 equals 0 find the discrimant?
Discriminant = (b2-4ac) = (25 - 4x2x3) = 1
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