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The discriminant in the quadratic formula is the expression?
b2-4ac
How do you factor 4x squared plus 4x -1?
Given 4x2+4x-1 Using the formula for the roots of quadratic equation, (-b +/-./b2-4ac)/2a the roots for the above will be (-4+/-4./2)/8 = (-1+/-./2)/2 Hence the two roots are (-1+./2)/2 and (-1-./2)/2 As the roots are irrational, there is no possibility of getting factors.
What is prime over the set of rational numbers?
trinomials that are prime over the set of rational numbers will NOT factor.A Tinomial ax^2 + bx + c 'will factor' if (b^2-4ac)is a perfect square or zero.
Is it possible to have a quadratic function with one real zero and one imaginary zero why or why not?
ax2+bx+c=0 with a,b and c real discriminant D=b2-4ac if D >0 then there are 2 real zeros if D = 0 then there is one real zero if D<0 then there are two imaginary zeros There are no other possibility for D For further information search for fundamental theorem of algebra
What two consecutive numbers multiply to make 2756?
Let's denote the two consecutive numbers as x and x+1. We can set up the equation x(x+1) = 2756. By expanding the left side of the equation, we get x^2 + x = 2756. Rearranging terms, we have x^2 + x - 2756 = 0. This is a quadratic equation that can be solved using factoring, the quadratic formula, or completing the square to find the two consecutive numbers.
