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The discriminant in the quadratic formula is the expression?
b2-4ac
How do you factor 4x squared plus 4x -1?
Given 4x2+4x-1 Using the formula for the roots of quadratic equation, (-b +/-./b2-4ac)/2a the roots for the above will be (-4+/-4./2)/8 = (-1+/-./2)/2 Hence the two roots are (-1+./2)/2 and (-1-./2)/2 As the roots are irrational, there is no possibility of getting factors.
What is prime over the set of rational numbers?
trinomials that are prime over the set of rational numbers will NOT factor.A Tinomial ax^2 + bx + c 'will factor' if (b^2-4ac)is a perfect square or zero.
Is it possible to have a quadratic function with one real zero and one imaginary zero why or why not?
ax2+bx+c=0 with a,b and c real discriminant D=b2-4ac if D >0 then there are 2 real zeros if D = 0 then there is one real zero if D<0 then there are two imaginary zeros There are no other possibility for D For further information search for fundamental theorem of algebra
What two consecutive numbers multiply to make 2756?
Let's denote the two consecutive numbers as x and x+1. We can set up the equation x(x+1) = 2756. By expanding the left side of the equation, we get x^2 + x = 2756. Rearranging terms, we have x^2 + x - 2756 = 0. This is a quadratic equation that can be solved using factoring, the quadratic formula, or completing the square to find the two consecutive numbers.
Factor 4ac plus 2ad plus 2bc plus bd?
(2a + b)(2c + d)
Factor this expression 4ac plus 2ad plus 2bc plus bd?
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
How do you factor this expression 4ac plus 2ad plus 2bc plus bd?
(2a + b)(2c + d).
Factor this expression check by multiplying factors.4ac plus 2ad plus 2bc plus 4bd?
ac + 2ad + 2bc + 4bd = a(c + 2d) + 2b(c + 2d) = (a + 2b)(c + 2d) Now expand to confirm your answer: c(a + 2b) + 2d(a + 2b) = ac + 2bc + 2ad + 4bd ≡ ac + 2ad + 2bc + 4bd
What does 4ac 2ad 2bc bd factor into?
(2a + b)(2c + d)
How do you factor 6x2-13x plus 15?
It cannot be factored because the discriminant of b2-4ac is less than zero.
How do you factor the expression 3x to the power of 2 plus 48x plus 192?
3x^2+48x+192=3(x^2+16x+62). You can factor the part in the parentheses using the quadratic formula: x= (-b[+-]Sqrt[b^2-4ac])/(2a).
What is a x squared plus b x plus c equals 0?
x = (-b (+/-) root( b2 - 4ac)) / 2a Sorry about the messy answer, there are no square root symbols or plus-minus symbols. Here is the proof - ax2 + bx + c = 0 --------> multiply by 4a 4a2x2 + 4abx + 4ac = 0 4a2x2 + 4abx = -4ac ----------> add b2 to both sides 4a2x2 + 4abx + b2 = b2 - 4ac -----------> factorise LHS (2ax + b)2 = b2 - 4ac 2ax + b = (+/-) root( b2 - 4ac) 2ax = -b (+/-) root( b2 - 4ac) x = (-b (+/-) root( b2 - 4ac)) / 2a Maths works people.
How do you factor 5t2 plus 20t plus 20?
This is a basic quadratic function. The easiest way to go about this is by using the quadratic formula.a=5 ; b=20 ; c=20-b + or - root (b2-4ac) all over 2a.
B2 -4ac in the quadratic equation ax2 plus bx plus c equals 0?
Full equation is (-b +/- sqrt(b2 - 4ac))/2a. Try it with x2 - 2x - 3, where a = 1, b = -2 and c = -3...
2x² plus 5x plus 3 equals 0 find the discrimant?
Discriminant = (b2-4ac) = (25 - 4x2x3) = 1
Does X2 plus 7x plus 18 equals factor?
X^2 + 7X + 18 = 0 try the discriminant b^2 - 4ac 7^2 - 4(1)(18) 49 - 72 < 0 so, no real roots and no factors of 18 add to 7
