x(x - 1)(4x - 15)
In the case of DC, and in AC when current and voltage are in phase, a volt-ampere is the same as a watt (and therefore, a kilo-volt-ampere is the same as a kW). In the case of AC, when current and voltage are NOT in phase, power = voltage x current x power factor; the power factor is the cosine of the angle between current and voltage, and it is always less than or equal to one. In such a case, a kVA would be less than a kW.
There is no special term "ac" in math, as far as I know. However, in physics, "AC" means "alternating current".
If the leading coefficient is 1 (or you don't see any number in front of x^2) then find 2 factors f1,f2 which multiply to get the constant term, c, and add to get the coefficient of x, or b,. Then the factors would be (x+f1)(x+f2). Always watch for negatives. Example: x^2 + 2x - 8 B= 2 C= -8 We want 2 numbers that multiply to -8 and add to 2. Since they multiply to a negative number, one must be positive and one must be negative. Since the sum is positive, the larger must also be positive. Analyzing signs can help with determining the factors. With our example, the factors would be 4, -2 so the factor of x^2 + 2x - 8 is (x + 4)(x - 2) To factor quadratic trinomials with a coefficient of the quadratic term , other than 1, I would try the AC method. Here is an example Factor 2x^2 - 3x - 2 With the AC method, find the product of the a, the coefficient of the quadratic term, and c, the constant Here AC = 2*-2 = -4 Then find your b, or coefficient of x B = -3 AC = -4 B = -3 To factor, you need to find a pair of factors that multiply to get AC but adds up to B Our factors would be -4 and 1 since -4*1 = -4 and -4 + 1 = -3 Then rewrite your factors (Ax + f1)(Ax + f2) where f1, f2 are the factors you just found. For our example, (2x - 4)(2x + 1). Finally, factor out any common factor from each binomial (here we can factor 2 out of 2x-4 to get (x - 2)(2x +1)) If this doesn't work, resort to the Quadratic Formula. The factors are then (x - (-b + sqrt(b^2-4ac))/2a)(x - (-b - sqrt(b^2 - 4ac))/2a)
The answer will depend on what ac is: it is not an abbreviation of any standard unit of length.The answer will depend on what ac is: it is not an abbreviation of any standard unit of length.The answer will depend on what ac is: it is not an abbreviation of any standard unit of length.The answer will depend on what ac is: it is not an abbreviation of any standard unit of length.
ac-5ad-5bc+25bd = a (c-5d) + 5b (c+5d) = ...
ac-5ad-5bc+25bd a(c-5d)-5b(c-5d) (a-5b)(c-5d) FOIL First (a*c=ac) Outside (a*-5d=-5ad) Inside (-5b*c=-5bc) Last (-5b*-5d=25bd) ac-5ad-5bc+25bd
(a - 5b)(c - 5d)
Power factor is an AC only term, and has no meaning for DC.
AC-1This applies to all AC devices (Resistive loads) with a power factor of at least power factor of 0.95 AC-3This applies to AC Inductive loads. Like squirrel cage motors.
The answer depends on whether or not a is a factor of c.
Per factor is 1 when reactive power is zero.
because of high resistance in the load.
(a - 2b)(c - 3d)
No difference in case of DC. In case of AC Watt refers to Power which includes the factor of power factor. VA does not include power factor.
ac bridges give the value of impedances like inductance, capacitance with high accuracy. it also tells us about the quality factor .
(a + b)(b + c)