(x - 2)(9y - 2)
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
(2x+4)(x+1)
a2 - 4a + 4
(3x + 4)(3x + 4)
To factor the polynomial (-x^3 + 2x^2 - 2x + 4), we can first factor out (-1), giving us (- (x^3 - 2x^2 + 2x - 4)). Next, we can use synthetic division or factor by grouping to find that (x^3 - 2x^2 + 2x - 4) factors to ((x - 2)(x^2 + 2)). Thus, the factored form of the original polynomial is (- (x - 2)(x^2 + 2)).
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
15x - 3xy = 3x(5 - y) 20 - 4y = 4(5 - y) 15x - 3xy + 20 - 4y = (3x + 4)(5 - y)
Not factorable
(2x+4)(x+1)
a2 - 4a + 4
(2x + 1)(x + 4)
Do in this order. 1. All, find the gfc 2. Binomial, factor as difference of squares, sum of cubes, difference of cubes. 3. Trinomial, factor as a quadratic. 4. 4 or more terms, factor by grouping.
(3x + 4)(3x + 4)
To factor the polynomial (-x^3 + 2x^2 - 2x + 4), we can first factor out (-1), giving us (- (x^3 - 2x^2 + 2x - 4)). Next, we can use synthetic division or factor by grouping to find that (x^3 - 2x^2 + 2x - 4) factors to ((x - 2)(x^2 + 2)). Thus, the factored form of the original polynomial is (- (x - 2)(x^2 + 2)).
If there are 4 or more terms in a problem, and none are like terms.
4(x + 1)(x + 1)
(x-1)(x+4)