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Factor the polynomial by grouping n3 plus 3n2 plus 4n plus 12?
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
Factor A2 plus 4a plus 4 - b2?
a2 - 4a + 4
Factor 2x2 plus 6x plus 4?
(2x+4)(x+1)
How do you factor the polynomial 9x2 plus 24x plus 16 with each factor as a polynomial in descending order?
(3x + 4)(3x + 4)
What is the factor of 25v plus 19v plus 4?
That's 44v + 4 which factors to 4(11v + 1)
Factor the polynomial by grouping n3 plus 3n2 plus 4n plus 12?
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
Factor the polynomial 15x - 3xy plus 20 - 4y by grouping?
15x - 3xy = 3x(5 - y) 20 - 4y = 4(5 - y) 15x - 3xy + 20 - 4y = (3x + 4)(5 - y)
Factor X2 plus 6X plus 4?
Not factorable
What are the rules of factorization?
Do in this order. 1. All, find the gfc 2. Binomial, factor as difference of squares, sum of cubes, difference of cubes. 3. Trinomial, factor as a quadratic. 4. 4 or more terms, factor by grouping.
How do you factor 2X2 plus 9x plus 4?
(2x + 1)(x + 4)
Factor A2 plus 4a plus 4 - b2?
a2 - 4a + 4
Factor 2x2 plus 6x plus 4?
(2x+4)(x+1)
When should you use factor by grouping as opposed to regular factoring?
If there are 4 or more terms in a problem, and none are like terms.
How do you factor the polynomial 9x2 plus 24x plus 16 with each factor as a polynomial in descending order?
(3x + 4)(3x + 4)
Factor 4x2 plus 8x plus 4?
4(x + 1)(x + 1)
Factor x squared plus 5x plus 4?
Oh, dude, you're hitting me with some math now? Alright, so you're looking at the quadratic expression x^2 + 5x + 4. To factor this, you want to find two numbers that multiply to 4 (the constant term) and add up to 5 (the coefficient of the x term). Those numbers are 1 and 4, so the factored form is (x + 1)(x + 4). That's it, easy peasy lemon squeezy!
How do you factor x2 plus 3x-4 plus 0?
(x-1)(x+4)
