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Is c3-5c2-36c a trinomial?
Yes
Factor of 5C2 plus 3C-2?
(5c - 2)(c +1)
What is the number of combinations for 2 out of 5 events?
There are 5C2 = 5*4/(2*1) = 10 combinations.
What is the probability of drawing two jacks and 3 tens of any suite from a standard deck of cards?
The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10
How many ways can you purchase 2 CDs if there are 3 to choose from 4 cassettes if there are 4 to choose from and 2 DVDs if there are 5 to choose from?
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
Is c3-5c2-36c a trinomial?
Yes
There are two sections in a question paper each contain five questions A students has to answer 6 questions?
he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
Factor of 5C2 plus 3C-2?
(5c - 2)(c +1)
20 c4 3c3 5c2 is this a monomial?
No. A monomial cannot have the variable c to different powers.
What is the number of combinations for 2 out of 5 events?
There are 5C2 = 5*4/(2*1) = 10 combinations.
What is the probability of drawing two jacks and 3 tens of any suite from a standard deck of cards?
The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10
How many parallelograms are formed when a set of 5 parallel lines intersect a set of 4 parallel lines?
This one is much more straightforward. There are 5C2 = 10 ways to choose two parallel lines from the set of five. There are 4C2 = 6 ways to choose two parallelograms from a set of four. Any parallelogram is uniquely determined by one pair of lines from the five, and one pair of lines from the four. Thus, the number of possible parallelograms is(5C2)*(4C2) = (10)*(6) = 60
How many ways can you purchase 2 CDs if there are 3 to choose from 4 cassettes if there are 4 to choose from and 2 DVDs if there are 5 to choose from?
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
What is the greatest number of lines determined by five points not three of which are collinear?
Since any two point must be collinear and must, therefore, define a line, the answer is 5C2, the number of combinations of two [points] out of five. This is 5*4/(2*1) = 10
How many rectangles in a 4 by 4 square?
To determine the number of rectangles in a 4 by 4 square, we can use the formula for the number of rectangles in an n by m grid, which is (n*(n+1)m(m+1))/4. In this case, n = 4 and m = 4, so the number of rectangles would be (4*(4+1)4(4+1))/4 = 40 rectangles. This includes all possible rectangles of different sizes that can be formed within the 4 by 4 square.
How many 5 letter combinations can be made from the alphabet if 3 are consonants and 2 are vowels?
There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.
What odd against a family that has five children has exactly two girls?
Depends, but assuming that you take the occurances of girls and boys born to be equal (Which for all intents and purposes they are). The number of possibilities is 5C2 which is worked out from the formula 5!/2!(5-2)! =120/12 =10 Each of the possibilities are 1/2*5 = 1/32 So the total possibility is 10/32
