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Q: What is the value of 5C2?
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Is c3-5c2-36c a trinomial?

Yes


There are two sections in a question paper each contain five questions A students has to answer 6 questions?

he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.


Factor of 5C2 plus 3C-2?

(5c - 2)(c +1)


How many rectangles in a 4 by 4 square?

100 A rectangle is formed by 2 horizontal lines and 2 vertical lines. There are 5 horizontal and 5 vertical lines so the number of rectangles is 5C2 * 5C2 = 10 * 10 = 100


20 c4 3c3 5c2 is this a monomial?

No. A monomial cannot have the variable c to different powers.


What is the number of combinations for 2 out of 5 events?

There are 5C2 = 5*4/(2*1) = 10 combinations.


What is the probability of drawing two jacks and 3 tens of any suite from a standard deck of cards?

The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10


How many parallelograms are formed when a set of 5 parallel lines intersect a set of 4 parallel lines?

This one is much more straightforward. There are 5C2 = 10 ways to choose two parallel lines from the set of five. There are 4C2 = 6 ways to choose two parallelograms from a set of four. Any parallelogram is uniquely determined by one pair of lines from the five, and one pair of lines from the four. Thus, the number of possible parallelograms is(5C2)*(4C2) = (10)*(6) = 60


How many ways can you purchase 2 CDs if there are 3 to choose from 4 cassettes if there are 4 to choose from and 2 DVDs if there are 5 to choose from?

The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.


What is the greatest number of lines determined by five points not three of which are collinear?

Since any two point must be collinear and must, therefore, define a line, the answer is 5C2, the number of combinations of two [points] out of five. This is 5*4/(2*1) = 10


How many 5 letter combinations can be made from the alphabet if 3 are consonants and 2 are vowels?

There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.


How many squares and rectangles are there in a 4 by 4 grid?

16 1x1 rectangles + 12 2x1 rectangles + 8 3x1 rectangles + 4 4x1 rectangles + 12 1x2 rectangles + 9 2x2 rectangles + 6 3x2 rectangles + 3 4x2 rectangles + 8 1x3 rectangles + 6 2x3 rectangles + 4 3x3 rectangles + 2 4x3 rectangles + 4 1x4 rectangles + 3 2x4 rectangles + 2 3x4 rectangles + 1 4x4 rectangle. A Grand Total of: 100 squares and rectangles. OR: A rectangle is formed by 2 horizontal lines and 2 vertical lines. There are 5 horizontal and 5 vertical lines so the number of rectangles is 5C2 * 5C2 = 10 * 10 = 100