x2 + 9 = (x + 3i)(x - 3i)
The answer is based on a knowledge of imaginary and complex numbers where i2 = -1
x2-6x+9 = (x-3)(x-3) when factorised.
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
(x - 7)(x - 9)
(X-9)2
(x - 3)(x - 3)
(x+1)(x+9)
x2-6x+9 = (x-3)(x-3) when factorised.
(x-9)(x+9)
x^(2) + 13x + 36 Factors to ( x + 9)(x + 4) When learning factoring. ;- #1 ; If the coefficient of x^(2) is '1' , as in this case. Then #2 ; Write down all the factors of 36, which are ,1,36 ' 2,18 ' 3,12 ' 4,9 ' 6,6 ; #3 ; Out of these pairs of factors, select a pair that add/subtract to '13'. #5, They are 4,9 ; 4 + 9 = 13 #6 ; Since the quadratic eq;m has positive (+) signs , then all the signs in the brackets are positive(+). When the coefficient of x^(2) is > 1, and/or the signs are different , then different techniques come into play.
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
(x + 3)(x + 3)
(x + 4)(x + 9)
x - 3
x2 - 14x + 45 = (x - 5)(x - 9).
(x+3)(x+3)
3(x2 - 2x + 3)
(x - 7)(x - 9)