Best Answer

(8x^2y^2)/9

2(4x^2-y^2)/9

2(2x+y)(2x-y)/9

Factored and reduced.

Q: Factorize 8x2- 2y2 over 9 completely?

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(8x2)-(13x-16)= -78

13y2 - 5yx - 8x2 = (y - x)(13y + 8x).

8x2 + 16x + 8 = 0

8x2+6x-35 = (2x+5)(4x-7) when factored

You could try dividing both numerator and denominator by 8x2 .

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2(4x2 + 6x - 1)

x(x+3)(x+5)

8x2 is 16 or 16/2=8

2(2x + 5)(2x - 5)

5-8x2-5x2 is equal to -21.

8x2 8x2

(8x2)-(13x-16)= -78

13y2 - 5yx - 8x2 = (y - x)(13y + 8x).

8x2 + 15 + 26x = 8x2 + 26x + 15 = 8x2 + 20x + 6x + 15 = 4x(2x + 5) + 3(2x + 5) = (2x + 5)(4x + 3)

8x2 + 16x + 8 = 0

51

16.