Best Answer

Let a = smallest number, then other numbers are a + 2 and a + 4

so a x (a +2) + 46 = (a + 4)^2

ie a^2 + 2a + 46 = a^2 + 8a + 16

this simplifies to 30 = 6a so a = 5 and the three numbers are 5, 7 and 9.

Check: 5 x 7 = 35, add 46 gives 91 = 9 squared.

Q: Find 3 consecutive odd numbers where the product of the smaller two number is 46 less than the square pf the largest number?

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