The original number, written as " T U ", has the value (10T + U). When you reverse the digits, the new number has the value (10U + T). Adding the two numbers: (10T + U) + (10U + T) = 55 11T + 11U = 11(T + U) = 55 T + U = 5 All possible two-digit numbers that satisfy (T + U = 5) are: 1423 32 41
whats the answer please??
38
Instead of reading the numbers from left to right (1234) read them from right to left (4321).
An emirp number is a prime number which, when you reverse the digits, produces a different prime number. Therefore, there are no single-digit emirp numbers. The first three emirp numbers are: 13, 17, 31
To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts. Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits. Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits. a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits. b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits. Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.
whats the answer please??
When multiplying numbers with significant digits, count the total number of significant digits in each number. Multiply the numbers as usual, but round the final answer to match the least number of significant digits in the original numbers.
38
Some numbers that you can get when you reverse the digits and they are still prime numbers are: 403 ÷ 13 = 31 2,701 ÷ 37 = 73 1,207 ÷ 17 = 71
Reverse the digits then check of the new number is the same as the original number.
To total 17 the two digits must be 8 and 9! The original number was 98.
Possibility of two digit no whose sum is 10 19,28,37,46,55,64,73,82,91 Now add 54 to each no mentioned above 73,82,91,100,109,118,127,136,145 See after 1st comma 28 and 82 Reverse of 28 is 82. That no 82 is 54 more than the no 28. So 28 is the original
Instead of reading the numbers from left to right (1234) read them from right to left (4321).
Prime numbers that remain prime when their digits are reversed are called emirps. Some examples of emirps include 13 (31), 17 (71), 31 (13), and 37 (73). These numbers are interesting because both the original number and its reverse are prime numbers.
2178 x 4 = 8712
The number is: 36725918 In descending order that is: 98765321 The pairs of numbers that have as many digits between them in both are: 3,9 5,8 6,7 So there are three pairs.
An emirp number is a prime number which, when you reverse the digits, produces a different prime number. Therefore, there are no single-digit emirp numbers. The first three emirp numbers are: 13, 17, 31