There is no way to find B 160 50 and 120 without knowing what these numbers correspond with. Once we know what the numbers correspond with then we can find the answer.
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Area = 2*(L*B + B*H + H*L) = 2*(10 + 20 + 50) = 2*80 = 160 cm3
A/b = 50/88 = 0.5681818181
a. 40 in.; 364 in.2b. 80 in.; 364 in.2c. 40 in.; 160 in.2d. 80 in.; 160 in.The answer is B. 80 in.; 364 in.2
This is solved by simultaneous equations. Perimeter = 2a + 2b = 100 where a and b are lengths of sides Area = a x b Rearranging the perimeter equation: 2a = 100 - 2b, a = 50 - b Putting this equation into the area equation: Area = (50 - b) x b = 50b - b x b Find the minimum/maximum by differentiating and setting to 0. Area' = 50 - 2b = 0, 2b = 50, b = 25 Area = 625cm sqare. when the length tends to 50, the area tends to 0. So the area can be anything from 0 to 625 cm
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